How long does it take it increase speed?

  • Thread starter RanHam335
  • Start date
  • #1
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Homework Statement


A freight train has a mass of 1.2e+7 kg. If the locomotive can exert a constant pull of 8.4e+5 N, how long does it take to increase the speed of the train from rest to 82 km/h?


Homework Equations


(mass*velocity)/time=force


The Attempt at a Solution


(1.2e+7 * 82)/h = 8.4e+5

i solved for h
h = (8.4e+5)/(9.84e+8)
h = 8.54e-4

then i had to convert from hours to min.
8.54e-4*60

so i got
5.1e-2 min

this is my first time posting on this forum so i hope i followed the right format.
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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82km/h = [itex]\frac{82*1000m}{3600s}[/itex]
 
  • #3
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can you explain the above?
 
  • #4
rock.freak667
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I just converted the speed from km/h to m/s which is usually what you should do.

82km/h

in 1h train travels 82km
=> in 1h train travels 82*1000m
in 3600s train travels 82000m
in 1s train travels 82000/3600 m

therefore the velocity in m/s is 820/36
 
  • #5
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that doesnt answer my question, i think im messing up on the formula. I have one submission left so i dont want to risk it
 
  • #6
rock.freak667
Homework Helper
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[tex]F=\frac{mv}{t} \Rightarrow t=\frac{mv}{F}[/tex]

[tex]t=\frac{(1.2*10^7 kg)*((\frac{82000}{3600} ms^-1)}{8.4*10^5 N}[/tex]



Can you calculate now?


But your answer was [itex]5.1*10^{-2}[/itex]minutes. Doesn't that seem like a small amount of time to go from 0 to 82km/h ?
 

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