How long does it take to move a box of books across the floor?

AI Thread Summary
The discussion focuses on calculating the time required to move a box of books weighing 329 N across a floor using a downward force of 484 N at an angle of 32 degrees. The key equations involve force, mass, and acceleration, with the coefficient of kinetic friction (μk) set at 0.57. An initial calculation yields an acceleration of approximately 2.03 m/s², but participants note discrepancies in the mass conversion and acceleration values. One contributor suggests that the mass should be calculated as 329 N divided by the acceleration due to gravity (9.81 m/s²), which affects the final result. The conversation highlights the importance of correct unit conversions and friction calculations in physics problems.
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Homework Statement


A box of books weighing 329 N is shoved across the floor by a force of 484 N exerted downward at an angle of 32◦ below the hori- zontal.
The acceleration of gravity is 9.81 m/s2 .
If μk between the box and the floor is 0.57, how long does it take to move the box 3.66 m, starting from rest?
Answer in units of s.

Homework Equations


Force=Mass(Acceleration)
X=1/2aT^2

The Attempt at a Solution


(Sigma)Fx=F(friction)+F(Applied)=ma
(Sigma)Fy=w+F(Normal)+F(Applied)=0

F(Normal)=329N + 484N(Sin32) = 585.481 ---->
F(Kinetic) = Mu(Kinetic)*F(Normal) ---> Fk = 0.57(585.481) = 333.724

-F(Kinetic)+F(Applied)(Cos32)
---------------------------------- = a -----> m=F(gravity)/(9.81)
m

-333.724 + 484(Cos32)
-------------------------- = 2.02893
329x=1/2at^2
3.66=1/2(2.02893)t^2
t=1.89942

I'm pretty sure I've done this correct, but the answer keeps coming out incorrect. Somebody please check my work.
 
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It looks like you used 329 as the mass instead of 329/9.81.
And something else went wrong in the same step to get a = 2.02.
Anyway, I get acceleration about 10% higher.
 
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