How long does it take to push this block at an angle?

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The discussion centers on calculating the time it takes for a 100 kg block to travel 100 meters when pushed at a 60-degree angle with a force of 20 Newtons on a frictionless surface. Participants highlight the ambiguity in measuring the angle and the need for clarification on whether it is from the vertical or horizontal. There is a correction regarding the kinematic equation used for position, emphasizing that the correct formula is D = Initial Velocity * Time + 0.5a*t^2. The conversation reflects confusion over the application of physics concepts and the importance of precise problem statements. Overall, the thread illustrates the complexities involved in solving physics problems with unclear parameters.
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Homework Statement


A 100 kg block is pushed across a level frictionless surface at a 60 degree angle, with a force of 20 Newtons. How many seconds does it take to go 100 meters?

m = 100kg
Mu = 0

Homework Equations


F = MA

The Attempt at a Solution


I sketched out the problem on my paper here, showing the downward angle force of 20N as Fx, and then the angle of 60 degrees being theta. From there it just turned into a mess of equations, some of which may be right, others which may not, and I was wondering if I did this problem correctly.

JcCVb70.jpg
 
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EthanVandals said:

Homework Statement


A 100 kg block is pushed across a level frictionless surface at a 60 degree angle, with a force of 20 Newtons. How many seconds does it take to go 100 meters?

m = 100kg
Mu = 0

Homework Equations


F = MA

The Attempt at a Solution


I sketched out the problem on my paper here, showing the downward angle force of 20N as Fx, and then the angle of 60 degrees being theta. From there it just turned into a mess of equations, some of which may be right, others which may not, and I was wondering if I did this problem correctly.

JcCVb70.jpg

You have the wrong equation for the last part. What is kinematic equation for position?
 
The problem is vague in that it doesn't specify how the angle is to be measured. Is it measured from the vertical? From the horizontal? It makes a difference.
 
gneill said:
The problem is vague in that it doesn't specify how the angle is to be measured. Is it measured from the vertical? From the horizontal? It makes a difference.
.. and is its vertical component up or down?
 
gneill said:
The problem is vague in that it doesn't specify how the angle is to be measured. Is it measured from the vertical? From the horizontal? It makes a difference.
Welcome to my world with my physics professor that drives me insane. I believe it's supposed to be how it is in the attached drawing. 60 degrees upward from the x axis.
 
EthanVandals said:
30 degrees upward from the x axis
The drawing has it acting downward from 30 degrees above the x axis. I assume that is what you mean.
Please respond to Student100's observation, that your equation D=at is wrong.
 
Student100 said:
You have the wrong equation for the last part. What is kinematic equation for position?

Ohh, it's D = InitialVelocity*Time + 0.5a*t^2, isn't it?
 
EthanVandals said:
Ohh, it's D = InitialVelocity*Time + 0.5a*t^2, isn't it?
Yes.
 
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