How long is an object in the air?

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To determine how long an object, like a kangaroo, is in the air after jumping to a height of 2.7 meters, the correct approach involves using the equation v^2 = u^2 + 2*a*s. Here, the final velocity (v) at maximum height is 0, acceleration (a) is -9.8 m/s², and displacement (s) is 2.7 m. By solving this equation, the initial velocity (u) can be calculated. Once the initial velocity is known, the time of flight can be easily determined. The answer key indicates that the total time in the air is 1.5 seconds.
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Homework Statement


I'm having trouble with questions such as: A kangaroo jumps to a vertical height of 2.7m. How long was it in the air before returning to earth?

Homework Equations


My guess is: vf2=2a(delta)x
but I am not certain.

The Attempt at a Solution


vf2=2*-9.8*2.7
it gave the wrong answer. The answer key says t=1.5sec. I need to know how to find this! Thanks
 
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Hi,
You find the incorrect velocity based on your attempt.
the equation used is v^2 = u^2 + 2*a*s, where v = final velocity, u = initial velocity, a = acceleration and s = displacement.
so at maximum height, v = 0 , s = 2.7 and a = -9.8 .
then you will be able to find your initial velocity of the kangaroo, u.

after that just find the time, which i think should be easy.
 
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