How long to heat a given volume of air?

AI Thread Summary
To determine the time taken for an 8kW air heater to raise the temperature of 9m^3 of air by 25°C, the calculations show that 0.35MJ of energy is required. This translates to approximately 0.097kWh, leading to a heating time of about 43 seconds. The discussion confirms that the calculations are correct and straightforward, emphasizing the importance of understanding the underlying principles. Additionally, there is a query about calculating the pressure of the air at 25°C, with a reference to the appropriate formula for pressure change. The conversation highlights the simplicity of the heating calculation when approached correctly.
evoke1l1
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Homework Statement


I am working on a problem where I need to determine the time taken for an air heater with an 8kW output to heat a volume of air of 9m^3 by 25C. I am neglecting all losses at the moment. It almost seems too simple in my mind that I'm concerned I'm overlooking something.

Homework Equations


cp = 1005 J kg-1 K-1
ρ = 1.534 kg m-3
Q = cp * m * dT

The Attempt at a Solution



Q = 1005 * (1.534 * 9) * 25 = 346875.75 J = 0.35MJ

As 1kWh = 3.6MJ:

0.35 / 3.6 = 0.097kWh required for a dT of 25C to heat a 9m^3 volume of air.

The time required would therefore be 0.097 / 8 = 0.012 hours or approximately 43 seconds.

Am I along the right lines here?
 
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Yes, you got it right. It really is that easy when you understand what you are doing.

Just for grins and giggles, what is the pressure of that air assuming the temperature is 25 deg C?
 
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Thank you for confirming this.

I’m assuming the change in pressure over the 25C change?

This would be caluculated by p2 = (p1 * T2) / T1 I believe.
 
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