How Long to Heat Ammonia Gas by 12°C with Solar Power?

AI Thread Summary
To determine the time required to heat 200 kg of ammonia gas by 12°C using solar radiation of 600 W, the specific heat capacity of ammonia at constant volume is needed. The total energy required can be calculated using the formula Q = mcΔT, where m is the mass, c is the specific heat capacity, and ΔT is the temperature change. The energy provided by the solar radiation over time can be expressed as E = P*t, where P is power and t is time. By equating the energy required to the energy provided, the time can be solved. The discussion emphasizes the need to calculate the number of moles of ammonia and its molar heat capacity for accurate results.
cash.money
Messages
14
Reaction score
0

Homework Statement



The sun heats 2.00 x 10^2 kg of ammonia gas that is kept at constant volume in a large tank. Assuming that solar radiation of 6.00 x 10^2 W caused the heating, determine the length of time it took to raise the ammonia's temperature by 12°C.


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
cash.money said:

Homework Statement



The sun heats 2.00 x 10^2 kg of ammonia gas that is kept at constant volume in a large tank. Assuming that solar radiation of 6.00 x 10^2 W caused the heating, determine the length of time it took to raise the ammonia's temperature by 12°C.
You will have to show us what you have done. How many moles of ammonia do you have? What is the molar heat capacity of ammonia gas at constant volume?

AM
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top