How Long to Move a Box with Angled Force and Friction?

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To determine how long it takes to move a 320 N box with a 430 N force at a 35.6° angle and a coefficient of kinetic friction of 0.57, the normal force must be calculated by considering all vertical forces. The equations for horizontal and vertical motion are correctly identified, but the challenge lies in finding the time from the acceleration. After calculating the net force and acceleration, the problem transitions into a kinematics scenario. Using the kinematic equation that relates distance, initial velocity, acceleration, and time will yield the required time to move the box 3.90 m. Properly applying these principles will lead to the solution.
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A box of books weighing 320 N is shoved across the floor of an apartment by a force of 430 N exerted downward at an angle of 35.6° below the horizontal. If the coefficient of kinetic friction between box and floor is 0.57, how long does it take to move the box 3.90 m, starting from rest?

I found n to be 260.19 but now i don't know where to go with it. What formula should I use? I can't find one that includes time.
 
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starfish794 said:
I found n to be 260.19 ...
What is "n" and how did you find this?

Hint: To calculate the normal force you must include all vertical forces acting on the books.
 
I personally am having trouble with this exact same question only with different numbers.
I have found so far, the equations:

m*a[x] = F[applied]*cos(Θ) - force of friction.
m*a[y] = F[normal] - F[gravity] - F[applied]*sin(Θ)

and

m*a = F[applied]*cos(Θ) - mu *(m*g + F[applied]*sin(Θ))

However I continually get the wrong answer no matter how I go about it and have no clue what I'm doing wrong, or even if those equations are right.

Any help would also be appriciated by me, greatly.
 
Stonie, your equations are all correct so post the calculation.
 
I solved those equations but I still don't understand how to find time from them. Help please?
 
Once you've solved for the acceleration, it becomes a kinematics problem.
 
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