How Long Was the Kangaroo in the Air?

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The discussion revolves around calculating the time a kangaroo spends in the air after jumping to a height of 2.8 meters. Participants clarify that the initial velocity and acceleration due to gravity must be considered, using kinematic equations. The kangaroo's jump is analyzed by first determining the initial velocity needed to reach the peak height, followed by calculating the time to ascend and then multiplying by two for the total air time. The correct total time in the air is determined to be approximately 1.52 seconds. The exchange highlights the importance of understanding the physics concepts behind the equations used.
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Why can't I understand simple vector questions? I've just started a higher physics and that's what we're learning.

I'm stuck with this question:

A kangaroo was seen to jump to a vertical height of 2.8m. How long was it in the air?

I have the answer at the back of the book, but I don't know how to arrive at the answer! Please help!

Do I need to split it up into the components:

u - initial velocity
v - final velocity
a - acceleration
s - distance
t - time

I know the equations, but when I plug the numbers in, it doesn't come out as the right answer!

:confused:
 
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is that all it says, must say how much Vi it has, or does it start from rest.
If it starts from rest you find the time it takes it to get to the top and then multiply by 2 and that's the total time, using the equation x=Vit + (1/2)at^2.
 
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two equations to be used here,
1>
Lets use the third kinematic eqn...
(using g down as positive sign so when direction of motion is upwards g is negative)
that gives us,
v^2=u^2-2gs

when it reaches maximum point , the final velocity becomes 0,
this gives v=0 and that gives us,
u^2 = 2gs
** we can calculate u since we know g and s

2>
now let's use the second kinematic equation,
s=ut+1/2at^2
from 1 we got 'u'
and we know a=-g and s=2.8
rearrange the equation and u get a quadratic in t
solve it to find t

But this t is the time to taken to reach the top we need the overall time which is just 2*t.

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I guess your right, looks like I messed up :frown: . Gj though. One more thing how does the kangaroo manage to jump up and straight down?, he must land a little to the side or sometin.
 
Why is that?
 
nm, sometimes i don't even know what I am typing but I just type it. :-p
 
That's all the information I'm given.

The answer is 1.5s, and I still don't know how to reach it! :frown:
 
Okay we have that
Vf=0 m/s
a=-9.81 m/s^2
x=2.8m

So in the equation

Vf^2 - Vi^2 = 2ax
0 - Vi^2 = 2 (-9.81)(2.8)
-Vi^2 = -54.936
Vi = 7.41m/s

Now in the equation

a = (Vi - Vf) / 2
-9.81 = (0-7.41) / t
-9.81t = -7.41
t = .76s

so that's only to the top so we multiply by 2, .76 * 2 = 1.52 s, which is the total time.
 
cdhotfire said:
so that's only to the top so we multiply by 2, .76 * 2 = 1.52 s, which is the total time.

That's what I didn't do! I now understand why I have to multiply it by two, I didn't think about that earlier! Thank you so much. :smile:
 
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No problem, glad I could help yout out. :cool:
 
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