How long would it take for a can of beer to fall over due to quantum tunneling?

AI Thread Summary
The discussion revolves around the concept of quantum tunneling and its application to a can of beer tipping over. Participants seek clarification on the mechanics of tunneling, particularly how particles might influence the can's position and the significance of the energy parameters used in the calculations. Questions arise about the frequency of attempts for the can to tip and the rationale behind setting the potential energy to zero at the center of the bottle. The conversation emphasizes the need for a deeper understanding of the quantum behavior involved in this scenario. Overall, the thread highlights the complexities of applying quantum physics to everyday objects.
lackrange
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It's on page 4 (this isn't homework, just something I stumbled upon, it's also in Griffith's 8.17):http://www.physics.udel.edu/~msafrono/425/Lecture 18.pdf .
Can someone help me understand this solution? What exactly is happening...are there particles at h/2 that are smashing against the bottle trying to tip it over? What exactly is tunneling? The solution makes it seem as if it is the center of the bottle that might spontaneously jump up to the critical point and then tip over, but then I don't understand what the frequency of attempts is, why the product should necessarily be 1 (is that just an arbitrary estimate we use for how long it will take to fall over?), and more importantly, why we are setting E=0...they set the potential energy to be 0 at the center of the bottle, but what about kinetic energy?
 
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Bump. Any ideas at all would be great.
 
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