How Many Angles Can a Quaternion Represent in 3D Space?

[Raparicio]

Dear Friends,

I've read about quaternions, and they can be expresed in 4 terms or in angles like this:

a + ib + jc + kd = cos \theta + \vec{v} sin \theta

Quaternions are a generalization of the complex numbers, but in 3D. My question is about angles. For example, with a complex number, we can write:

a + ib = sin \theta + i \theta

By generalization, is this ok?

a + ib + jc + kd = cos \theta + i sin \theta + j sin \theta + k sin \theta

By other hand, we can take the angles in complex numbers like:

a + ib = cos \theta + i sin \theta --> Only one angle

how much angles has a quaternion? has angle with the real part?

my best reggards.

 

[neurocomp2003]

quaternion represents 1 angle...it represents a matrix rotation

you can multiple quaternions to get another quaternion just like you
can multiple M*M

 

[James R]

Raparicio:

I'm not sure you're correct.

a + ib + jc + kd = cos \theta + \vec{v} sin \theta

I do not think that would work, since the possible values of \cos \theta are limited to values between 1 and -1, while a, for example, has no such limit.

For example, with a complex number, we can write:

a + ib = sin \theta + i \theta

That is incorrect for general a and b, because you can see by inspection that it requires

a=\sin \theta, b=\theta

which would mean a=\sin b, which need not be true for a general complex number.

a + ib + jc + kd = cos \theta + i sin \theta + j sin \theta + k sin \theta

Again, that's wrong, because it implies that b=c=d, which need not be true for a general quaternion.

By other hand, we can take the angles in complex numbers like:

a + ib = cos \theta + i sin \theta --> Only one angle

Actually, this isn't general enough. You need

a + ib = r [cos \theta + i sin \theta]

(i.e. an extra parameter, r, is requied).

 

[BobG]

Dear Friends,

I've read about quaternions, and they can be expresed in 4 terms or in angles like this:

a + ib + jc + kd = cos \theta + \vec{v} sin \theta

Quaternions are a generalization of the complex numbers, but in 3D. My question is about angles. For example, with a complex number, we can write:

a + ib = sin \theta + i \theta

By generalization, is this ok?

a + ib + jc + kd = cos \theta + i sin \theta + j sin \theta + k sin \theta

By other hand, we can take the angles in complex numbers like:

a + ib = cos \theta + i sin \theta --> Only one angle

how much angles has a quaternion? has angle with the real part?

my best reggards.

Almost correct.

If \vec{v}=ib + jc + kd
Then cos \theta + \vec{v} sin \theta=\cos \theta + ib \sin \theta + jc \sin \theta + kd \sin \theta

 

[Raparicio]

exponencial

Almost correct.

If \vec{v}=ib + jc + kd
Then cos \theta + \vec{v} sin \theta=\cos \theta + ib \sin \theta + jc \sin \theta + kd \sin \theta

Aha!

And in exponential:

Then a·cos \theta · e^{ib \theta + jc \theta + kd \theta ?

 

[BobG]

Aha!

And in exponential:

Then a·cos \theta · e^{ib \theta + jc \theta + kd \theta ?

I'm not positive if you're talking about quaternions in general.

However, what you're doing is normally used with unit quaternions. They'll always have a magnitude of 1. As nuerocomp2003 mentioned, they're used for vector transformation. The change the angles associated with the vector they're used on, but dont' change the magnitude of the vector they're used on.

With that in mind, I'm pretty sure you'll wind up simply with:

e^{(u \theta)} where u is the unit vector whose i,j,k components are the direction cosines of the unit vector.

In other words, the a \cos \theta part is not correct for a unit quaternion. The exponent part is correct.

 

[Raparicio]

exactly

I'm not positive if you're talking about quaternions in general.

However, what you're doing is normally used with unit quaternions. With that in mind, I'm pretty sure you'll wind up simply with:

e^{(u \theta)} where u is the unit vector whose i,j,k components are the direction cosines of the unit vector.

Exactly! (im talking about unit quaternions).