Chemistry How many atoms are there in 3.90 moles of sulfur (S)?

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To find the number of atoms in 3.90 moles of sulfur (S), multiply the number of moles by Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole. This calculation yields about 2.35 x 10^24 atoms of sulfur. Understanding the relationship between moles and Avogadro's number is crucial for solving such problems. The periodic table provides essential information about the element, but the key is applying the mole-to-atom conversion. This method is fundamental in chemistry for quantifying substances at the atomic level.
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I need help could someone please help me with this problem?
How many atoms are there in 3.90 moles of sulfur (S)?
 
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This is similar to the other question you posted. Post some thoughts on what information you might need from the periodic table.
 
Does Avogadro's (or Loschmidt's) number mean anything?
 
How many atoms are in one mole of sulfur?
 
just like the above you must start out with your given mass and show the relationship between mole value(s) and avagadros number
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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