How Many Excess Electrons Are on a Charged Rod with Nonuniform Density?

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The discussion focuses on calculating the number of excess electrons on a charged nonconducting rod with both uniform and nonuniform charge densities. For the uniform density of -4.22 µC/m³, the calculation yields approximately 1.193 x 10^10 electrons. In the case of the nonuniform density defined by ρ = bx² with b = -2.66 µC/m⁵, the initial calculation of excess electrons was found to be incorrect due to a miscalculation in the integration process and unit conversion. Participants suggest checking the units of b and applying the correct conversion factor from microcoulombs to coulombs to resolve the discrepancy. The thread emphasizes the importance of careful unit management in physics calculations.
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Homework Statement


A charged nonconducting rod, with a length of 1.33 m and a cross-sectional area of 3.40 cm2, lies along the positive side of an x axis with one end at the origin. The volume charge density ρ is charge per unit volume in coulombs per cubic meter. How many excess electrons are on the rod if ρ is (a) uniform, with a value of -4.22 µC/m3, and (b) nonuniform, with a value given by ρ = bx2, where b = -2.66 µC/m5?

Homework Equations


q=ne
p=bx^2

The Attempt at a Solution


So for part a:
n=(p(a)L)/e
n=(-4.22E-6C)(3.4E-4m^2)(1.33m)/(-1.6E-19C)
n=1.193E10 electrons

Part b is where i was incorrect
p=bx^2
p=-2.66x^2
dq=Apdx
=3.4E-4*-2.66x^2dx
so q=9.04E-4* the integral of x^2dx from 0 to 1.33
q=-7.09E-4C
n=q/e
=-7.09E-4C/-1.6E-19C
=4.431E15 electrons<----- this was incorrect and I am unsure of my mistake
 
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Jrlinton said:
Part b is where i was incorrect
p=bx^2
p=-2.66x^2
dq=Apdx
=3.4E-4*-2.66x^2dx
so q=9.04E-4* the integral of x^2dx from 0 to 1.33 ⇐
q=-7.09E-4C
n=q/e
=-7.09E-4C/-1.6E-19C
=4.431E15 electrons<----- this was incorrect and I am unsure of my mistake

Looks like the order of magnitude went astray starting here. 10-4 is too big. Check the units of the constant b.
 
Right, so multiply the final answer by the conversion factor of microcoulombs to coulombs of E-6.
 
That'll work.
 
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