How Many People Can an Elevator Hold Without Breaking the Cable?

AI Thread Summary
An elevator cable can safely hold a maximum tension of 13,000 N, which is two-thirds of its breaking tension of 19,500 N. Given the elevator's mass of 490 kg and a maximum acceleration of 2.24 m/s², the calculations show that the elevator can accommodate approximately 9 additional 65-kg people. The net force acting on the elevator includes both the tension in the cable and the gravitational force. The discussions emphasize the importance of considering both the weight of the elevator and the acceleration due to gravity in these calculations. Ultimately, the conclusion is that the elevator can safely hold 9 people without exceeding cable tension limits.
Voltrical
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Homework Statement



1) An elevator cable can withstand a maximum tension of 19,500N before breaking. The elevator has a mass of 490 kg and a maximum acceleration of 2.24 m/s2. Engineering safety standards require that the cable tension never exceed two-thirds of the breaking tension. How may 65-kg people can the elevator safely accommodate?



Homework Equations




F = ma


The Attempt at a Solution



F = ma

F = (2/3)*(19,500 N)
F = 13,000 N

Then:

n = { [(13,000 N) / (2.24 m/s^2)] - 490 kg } / 65 kg
n = 81.7

n = 81 people
 
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Do not forget gravity. The cable exerts the upward tension T and gravity exerts the downward force mg. The resultant of these forces accelerate the elevator upward.

ehild
 
Voltrical said:
n = { [(13,000 N) / (2.24 m/s^2)] - 490 kg } / 65 kg
In addition to what ehild said, don't forget that the entire elevator, people plus car, are accelerating.
 
This is what I've gotten so far.

Since "require that the cable tension never exceed two-thirds of the breaking tension" :
F = ma
F = (2/3)*(19500)
F = 13000

Max Acceleration = 2.24 m/s^2
Acceleration due to gravity = 9.81 m/s^2
Acceleration = 2.24 + 9.81 = 12.05 m/s^2

So,

F = ma
13000 = ((490kg)+(65kgx))(12.05m/s^2)
x = 9.059 people

Rounded it to 9 people.
 
Voltrical said:
This is what I've gotten so far.

Since "require that the cable tension never exceed two-thirds of the breaking tension" :
F = ma
F = (2/3)*(19500)
F = 13000

Max Acceleration = 2.24 m/s^2
Acceleration due to gravity = 9.81 m/s^2
Acceleration = 2.24 + 9.81 = 12.05 m/s^2

So,

F = ma
13000 = ((490kg)+(65kgx))(12.05m/s^2)
x = 9.059 people

Rounded it to 9 people.

Your "F" is the tension in the cable.

The elevator is accelerated by the sum of both forces: tension and gravity. The net force on the elevator is T-mg upward. So ma=T-mg.

Rearranging the equation, it becomes the same you used. T=m(a+g). The result is correct.

ehild
 
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Oh that makes sense now ehild.

Thanks a lot guys, the help is much appreciated.
 
Voltrical said:
Oh that makes sense now ehild.

Thanks a lot guys, the help is much appreciated.

You are welcome:smile:

ehild
 
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