How many solutions does the equation have?

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Homework Help Overview

The problem involves finding the number of solutions to the equation \(x_1 + x_2 + x_3 = 17\) under specific constraints: \(0 \leq x_1 < 6\), \(x_2 \geq 0\), and \(x_3 > 5\). The context suggests a combinatorial counting approach may be relevant.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of the variables, questioning whether they are integers and what values they can take. There is mention of counting solutions for each possible value of \(x_1\) and how that relates to \(x_2\) and \(x_3\). Some participants suggest trying different values for \(x_2\) to find a pattern in the number of solutions.

Discussion Status

The discussion is active, with participants exploring various counting methods and questioning assumptions about the problem. Some guidance has been offered regarding setting specific values for \(x_2\) and counting corresponding solutions for \(x_1\) and \(x_3\). There is a recognition of potential patterns in the solutions as participants share their findings.

Contextual Notes

There is an implicit assumption that \(x_1\), \(x_2\), and \(x_3\) are integers, which has not been explicitly stated in the original problem. Participants are also considering the implications of the constraints on the values of \(x_1\), \(x_2\), and \(x_3\>.

terryds
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Homework Statement


If ## 0 \leq x_1 < 6, x_2 \geq 0, x_3 > 5##, how many solutions does ##x_1+x_2+x_3=17## have ?

A.46
B.57
C.68
D.79
E.89

Homework Equations

The Attempt at a Solution



For x3, ## 17 - x_1 - x_2 > 5 ##
For x2, ## 17 - x_1-x_3 \geq 0 ##
For x1, ## 0 \leq 17 - x_2 - x_3 < 6 ##

Then, I don't know what to do next..
Please help
 
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Is this the whole problem?

I would expect them to say that x1, x2 and x3 are integers.

What can you say about x1? What values can it take?

Similarly for the others.

Basically this is a counting problem, ie for each x1 value count the number of x2 and x3 values that make the x1+x2+x3=17 true.
 
jedishrfu said:
Is this the whole problem?

I would expect them to say that x1, x2 and x3 are integers.

What can you say about x1? What values can it take?

Similarly for the others.

Basically this is a counting problem, ie for each x1 value count the number of x2 and x3 values that make the x1+x2+x3=17 true.

So, there is no better way than trying each one ??
I think there's a better way since all of the options are a bit big numbers (46 is the smallest)
 
There probably is a better way but since you don't see it yet then why not try to count them.

Pick x2 and set it to 0 then how many choices are there for x1 and x3?
 
jedishrfu said:
There probably is a better way but since you don't see it yet then why not try to count them.

Pick x2 and set it to 0 then how many choices are there for x1 and x3?
There are seven choice..
(0,17),(1,16),...,(6,11)
 
Close but x1 =/= 6

now try x2=1 then x2=2 ...

If you can spot the pattern that's great but you might be able to eliminate some of the choices like say is 89 too high a count?
 
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So there is 6 solutions for x2 = 0
If x2 = 1, then there will be 6 solutions also
So, for x2 = 0 until x2 = 6, it will have 6 solutions.
But for x2=7, there are 5 solutions.
For x2 = 8, there are 4 solutions... and so on

So, by trying each integer for x2 value, there are 7*6+5+4+3+2+1 = 57 solutions.. Got it! Thankss
 

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