How Many Ways Can Delegates Be Arranged at a Conference Table?

AI Thread Summary
The problem involves arranging 15 delegates from 5 delegations of 3 members each at a round table, with the condition that each delegation sits together and the leader is in the middle. The total arrangements start with 14! for the circular arrangement of the groups. Additionally, each delegation can be arranged in 2 ways, leading to a calculation of 2^5 for internal arrangements. Therefore, the total number of arrangements is given by 4! multiplied by 2^5. The final conclusion is that the arrangement must account for both group positioning and internal delegation arrangements.
Jshua Monkoe
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Homework Statement



At a conference of 5 powers,each deligation consists of 3 members. If each delegation sits together, with the leader in the middle, in how many ways ca the members be arranged at a round table?



Homework Equations



No. of ways of arranging n objects around a circle=(n-1)!
P(n,r)=n!/(n-r)!


The Attempt at a Solution



I understand that 15 people go around the table
=> no. of ways to arrange=14!
But again in their different delgations,each can be arranged 2!/(2-2)!=2ways
=> There are 2(15) ways to arrange within the delegations
.'. there are 14!(30) ways
IS THIS CORRECT?
 
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We can not consider 15 people as a whole since we do not have complete flexibility regarding their arrangement.
Since there are 5 groups which always individually sit together, there are 4! ways in which the groups can be organized on the table.
Now, each group can internally have 2 possible arrangements. => 2^5 arrangements in all.
i.e. Total no. of permutations = 4! * 2^5
 
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