How many ways can French and Spanish books be arranged on a shelf?

  • Thread starter Thread starter mtingt
  • Start date Start date
  • Tags Tags
    Books Probability
AI Thread Summary
The discussion revolves around arranging 7 French and 7 Spanish books on a shelf under two conditions. For the first scenario, where books of the same language must be grouped together, the correct arrangement is calculated as 7! x 7!. In the second scenario, where the books must alternate starting with a French book, participants debate the approach, ultimately agreeing that the arrangement can also be expressed as 7! x 7!. Various arguments are presented to support the equivalence of methods, emphasizing that both scenarios yield the same result. The conversation highlights the importance of understanding combinatorial principles in arranging items with specific constraints.
mtingt
Messages
13
Reaction score
0

Homework Statement


there are 7 different french books and 7 different Spanish books, how many ways are there to arrange them on a shelf
a. books of the same language must be group together, French on left and Spanish on Right?
b. French and Spanish books must alternate in the grouping, beginning with a French book?

I tried doing 7!x7! for both of them but i don't think i am right?

I have no idea how to approach this
 
Physics news on Phys.org
mtingt said:
I tried doing 7!x7! for both of them but i don't think i am right?
Sounds right to me.
 
for the first one 7!x7! seems right, but for the 2nd one I think (not sure...!) it's :

7C1X7C1 X 6C1X6C1 X 5C1X5C1 X 4C1X4C1 X 3C1X3C1 X 2C1X2C1 X 1C1X1C1
 
MadAtom said:
for the first one 7!x7! seems right, but for the 2nd one I think (not sure...!) it's :

7C1X7C1 X 6C1X6C1 X 5C1X5C1 X 4C1X4C1 X 3C1X3C1 X 2C1X2C1 X 1C1X1C1
I think an argument could go: there are 14 choices for the first book, (French or Spanish). There are then 7 choices for the next book (If first was French, this one must be Spanish), then 6 choices for next, (has to be French), then 6 choices for next (has to be Spanish)...and so on. In this Q, the French book is first so what you wrote is correct.
 
Last edited:
CAF123 said:
I think an argument could go: there are 14 choices for the first book, (French or Spanish). There are then 7 choices for the next book (If first was French, this one must be Spanish), then 6 choices for next, (has to be French), then 6 choices for next (has to be Spanish)...and so on. In this Q, the French book is first so what you wrote is correct.

Another argument: for each arrangement of the French books, leave a space between successive books and fill those spaces with the Spanish books, one book per space.

RGV
 
Last edited:
MadAtom said:
for the 2nd one I think it's :
7C1X7C1 X 6C1X6C1 X 5C1X5C1 X 4C1X4C1 X 3C1X3C1 X 2C1X2C1 X 1C1X1C1
How is that different from 7!x7!?
The two obviously have the same answer. Either way, there is a fixed set of 7 positions that can be taken by the French books, and another fixed set of 7 that can be taken by the Spanish, independently.
 
haruspex said:
How is that different from 7!x7!?
The two obviously have the same answer. Either way, there is a fixed set of 7 positions that can be taken by the French books, and another fixed set of 7 that can be taken by the Spanish, independently.

It's not different; it's just another argument that the OP may, or may not, prefer.

RGV
 
Ray Vickson said:
It's not different; it's just another argument that the OP may, or may not, prefer.
RGV
I was replying to MadAtom, who wrote:
the first one 7!x7! seems right, but for the 2nd one I think (not sure...!) it's :​
Seems to me MadAtom implied 7!x7! was wrong for the second question.
 
haruspex said:
Seems to me MadAtom implied 7!x7! was wrong for the second question.

I thought so, but the result is the same... sorry.
 
Back
Top