How Much Effort is Needed to Move a 2000 lb Object 50 ft?

  • Thread starter Thread starter 9000_red
  • Start date Start date
  • Tags Tags
    Figure
AI Thread Summary
To move a 2000 lb object horizontally, no work is required if friction is ignored, as work is defined by the force applied over a distance. However, if friction is considered, the effort needed depends on the friction coefficient between the object and the surface. For a pallet moved on smooth concrete, the friction coefficient is approximately 0.01 to 0.02, which means calculating the force of friction is essential to determine the effort needed to initiate movement. The discussion emphasizes that understanding the concepts of work and friction is crucial for accurately assessing the effort required. Ultimately, the amount of force needed to get the pallet rolling is directly tied to overcoming friction, not the weight of the person moving it.
9000_red
Messages
7
Reaction score
0
let's say a 180 lbs person needs to move a 2000 lbs object 50 feet. that would take 100,000 ft/lbs. how do you apply that in terms of how much effort it would take from a 180lbs man? divide by 180 and get 555.5? how do you determine the amount of force required to get this object rolling? this doesn't have to be exact, so friction etc doesn't have to be taken into account for my purposes...
 
Physics news on Phys.org
I don't see how the person's weight has anything to do with it.
Looks to me like you have learned some formulas, but no concepts!

Moving a 2000 lb. object 50 feet horizontally would not require 100000 ft-lbs of work. Ignoring friction, it would require no work at all. Moving it 50 feet vertically upward would require 100000 ft-lbs of work because it would have acquired 100000 ft-lbs of potential energy.
 
i'm trying to figure out how much effort it takes for a man to pull a pallet of cokes (2000lbs) from one point in a grocery store to another (50ft). if the pallet is moved by a jack with polyurethane wheels across smooth concrete, or tile floors like in wal-mart, the friction coefficient would be

Hardrubber on Concrete f = 0,01 -0,02m

but I'm no math whiz, honestly i suck at most of it... but what's the simplest way to say it would take a guy _ lbs of effort to get this pallet rolling...
 
bump 4 help
 
HINT: Calculate how much work is done by the force of friction.
 
As I said before, if you are moving something horzontally and ignore friction, there will be no work done at all. All the work in this problem depends on the friction.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top