How much energy is dissipated by the 25 ohm resistor?

iceman887
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Homework Statement



A 0.25 UF capacitor is charged to 50 V. It is then connected in series with a 25 ohm resistor and a 100 ohm resistor and allowed to discharge completely.

Homework Equations


P=I V=I^2R=(V^2)/R


The Attempt at a Solution


i'm not sure how to approach this problem. it hink there is formula i need that missing for calculating energy
 
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I can't remember exactly how it works, but if you go to allaboutcircuits.com you will find every bit of info for this type of problem. We actually used that site as the textbook when I took Electronics and Circuit Theory courses
 
The energy stored in a capacitor is (1/2)CV^2. Initially, V=50 Volts. After the capacitor is completely discharged, the potential across it is clearly zero. so how much energy must have been dissipated?
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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