How Much Force Is Needed to Move a 1960 N Block of Dry Ice?

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To move a 1960 N block of dry ice on a walkway with a coefficient of friction of 0.125, a force of at least 245 N must be exerted. This calculation is derived by multiplying the weight of the block by the coefficient of friction, which provides the maximum frictional force. The discussion clarifies that the normal force is equivalent to the gravitational force in this scenario. To initiate movement, the applied force must meet or exceed the calculated frictional force. Understanding these principles is essential for accurately determining the force required to overcome static friction.
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16. A block of dry ice weighing 1960 N is lying on a walkway. The coeffi cient of friction of
the walking surface is 0.125. With what force must you push or pull the block to move it?
A. 1.57 x 104 N
B. 1960 N
C. 245 N
D. 6.38 x 10-5 N
(For this I multiplyed 1960N (which is the Fn or fg) by the coefficient of friction on the walking surface which is 0.125)
Is this correct?
 
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The answer is correct.
The force [question: should you take gravitational or normal force here? e.g. on an inclined surface, these are not equal] multiplied by coefficient of friction gives the maximal frictional force. To get the block moving, you should exert at least this force [question: which physical law tells you that?].
 

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