How Much Force Stops a Hailstone Mid-Damage?

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A hailstone weighing 0.012 kg and traveling at 20 m/s created a 0.20 cm dent in a car's hood, prompting a calculation of the average force exerted by the car to stop the hailstone. The momentum of the hailstone was calculated using the formula p=mv, leading to a derived average force of 1200 N. The discussion also touched on the relationship between average force and change in momentum, highlighting the importance of understanding these concepts in physics. The initial confusion was resolved, indicating a successful grasp of the problem. Overall, the thread emphasizes the application of physics equations to real-world scenarios involving impacts.
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Homework Statement


During an autumn storm, a 0.012kg hail stone traveling at 20.0m/s made a 0.20cm deep dent in the hood of Darnell's new car. What average force did the car exert to stop the damaging hail stone?
m= 0.012kg
v= 20m/s
d= .002m


Homework Equations


p=mv
j= f delta t


The Attempt at a Solution



I'm just confused :/
 
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Never mind, I was able to solve it. :D

.012kg * 1/2(20m/s)^2 / .002m = 1200 N

Too easy :)
 
Hello Marco! What is the relation between average force and change in momentum?
 
That's good!
 

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