How Much Force to Open a Cooled Pot Lid?

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To determine the force needed to open a cooled pot lid, the initial conditions include a temperature of 80 °C and a final temperature of 15 °C. The diameter of the pot is 20 cm, and the atmospheric pressure is 1.0 bar. The force can be calculated using the formula F = Area x Pressure, where the area is derived from the pot's diameter. The ideal gas law can be applied to find the final pressure in the pot after cooling. Ultimately, the calculated force required to separate the lid from the pot is 580 N.
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A pot is closed tightly with a lid when the temperature of the air in the pot is 80 oC. The temperature of the system then drops to 15 oC. Find the force needed to pull the lid and the pot apart. The diameter of the pot is 20 cm, and the atmospheric pressure is 1,0 bar.

The ANSWER is F = 580 N but I don't know how to get it, I got F = Area x Pressure but so confused about the final pressure.
 
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mrlac1212 said:
A pot is closed tightly with a lid when the temperature of the air in the pot is 80 oC. The temperature of the system then drops to 15 oC. Find the force needed to pull the lid and the pot apart. The diameter of the pot is 20 cm, and the atmospheric pressure is 1,0 bar.

The ANSWER is F = 580 N but I don't know how to get it, I got F = Area x Pressure but so confused about the final pressure.
Are you familiar with the ideal gas law?
 
Chestermiller said:
Are you familiar with the ideal gas law?
yeah right, it in Ideal Gas chapter, with nR = pV/T
 
mrlac1212 said:
yeah right, it in Ideal Gas chapter, with nR = pV/T
You can find the final pressure in the pot by using this equation.
 

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