How Much Gravity Does a Black Hole Need to Contain Light?

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To become a black hole, an object's mass must be compressed within its Schwarzschild radius, defined by the equation r_s = 2GM/c^2. The discussion explores how many Earth-sized masses would need to be compressed to create a black hole the size of Earth. It concludes that a black hole with the mass of Earth would require approximately 700 million Earths to achieve the necessary density. The conversation highlights the complexities of calculating the gravitational force required for a black hole and the implications of its space-time curvature on light. Ultimately, the topic emphasizes the relationship between mass, size, and the formation of black holes.
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what's the amount of gravity or exactly how many "Gees" a black hole must exert to be a black hole (strong enough gravity to contain any light it "emits")?
 
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realizing that in order to do such a calculation we would need a "size" for the thing.

hmm that complicates matters

let's assume the "Black Hole" is the size of the earth. how many "Earth's" do we need to compress to the size of ONE Earth to create a black hole?
 
To become a black hole, all the mass of an object must be within its Schwarzschild radius,

r_s = \frac{2 G M}{c^2}

That is the only condition.

- Warren
 
How can a black hole "emit" any light at all? If I'm not mistaken, light "falls" into a black hole. Once the light get's too close to the black hole, it is affected by the black hole's space-time curvature. The space-time curvature is so inclined that light falls in, but can not get back out. I dunno. :smile:
 
sweet, thanks chroot that's exactly what i was looking for :D

now i just need to acquire 700 million more Earth's...
 
terrabyte said:
sweet, thanks chroot that's exactly what i was looking for :D

now i just need to acquire 700 million more Earth's...

"If we had but world enough and time!"
 

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