How much heat (calories) is required to raise the temperature

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SUMMARY

The calculation of heat required to raise the temperature of 20 g of water from 15°C to 95°C involves using the specific heat capacity of water, which is 1.0 cal/g°C. The temperature change is 80°C, resulting in a total heat requirement of 2400 calories. The formula Q = mcΔT is applicable when using Joules and kilograms, where 'c' represents the specific heat capacity. This straightforward approach confirms the efficiency of the metric system in thermal calculations.

PREREQUISITES
  • Understanding of specific heat capacity
  • Basic knowledge of calorimetry
  • Familiarity with temperature scales (Celsius)
  • Ability to perform unit conversions between calories and Joules
NEXT STEPS
  • Study the formula Q = mcΔT in detail
  • Learn about calorimetry and its applications in thermal physics
  • Explore the conversion between calories and Joules
  • Investigate the specific heat capacities of other substances
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Students in physics or chemistry, educators teaching thermodynamics, and anyone interested in understanding heat transfer and calorimetry principles.

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Homework Statement


How much heat (calories) is required to raise the temperature of 20 g water from 15oC to 95oC? The specific heat capacity of water is 1.0 cal/g*oC.


Homework Equations





The Attempt at a Solution



95-15 = 80oC
80oC *30 g = 2400 cal.

Is that basically what you have to do? Or is there a more formal equation to use?
 
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No - it is that simple.
The definiation of a calorie is the energy needed to heat 1g of water 1deg C - isn't the metric system wonderful!

If you are working in Joules and Kg the equation is Q = mcT Where 'c' is the specific heat capacity - the number of Joules needed to heat 1kg of water by 1deg C.
 

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