Q = cm t (raising water temperature -- answer given looks wrong)

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SUMMARY

The discussion centers on the calculation of heat energy required to raise the temperature of 300 grams of water from 22 degrees Celsius to 30 degrees Celsius using the formula Q = cmΔt. The specific heat capacity (c) is given as 1 cal/g°C. The correct calculation shows that Q equals 2400 calories, as Δt (the change in temperature) is 8 degrees Celsius, leading to Q = 1 cal/g°C * 300 g * 8°C = 2400 cal. The initial assertion of 300 cal is incorrect based on the provided values.

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Stacie Worrel
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Hey ya'll my question reads:
Use the formula Q = cmt to show that 300 cal are requited to raise the temperature of 300g of water from 22 degrees C to 30 degrees C. For the specific heat capacity c, use 1 cal/g degrees C.

now i don't see how this math adds up, doesn't that equal 2400?

Thanks in advance!
 
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It seems like you are right. Assuming you wrote the problem as it is in the source.
 

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