How Much Ice Was in the Calorimeter Initially?

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SUMMARY

The discussion focuses on a calorimetry problem involving a 50 g aluminum calorimeter containing a mixture of 95 g of water and ice at 0 degrees Celsius. When 100 g of aluminum heated to 100 degrees Celsius is introduced, the final temperature of the mixture rises to 5 degrees Celsius. The objective is to determine the initial mass of ice in the mixture using the specific heat capacity of aluminum, which is 0.22 cal/g°C. Key principles include the conservation of energy, where heat gained equals heat lost, and the application of heat transfer equations.

PREREQUISITES
  • Understanding of heat transfer principles
  • Familiarity with calorimetry concepts
  • Knowledge of specific heat capacity calculations
  • Proficiency in applying conservation of energy laws
NEXT STEPS
  • Review heat transfer equations in thermodynamics
  • Study phase change equations relevant to calorimetry
  • Learn about specific heat capacity calculations for different materials
  • Practice problems involving conservation of energy in calorimetry scenarios
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, educators teaching calorimetry, and anyone interested in understanding heat transfer and energy conservation in physical chemistry contexts.

boomboompoop
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id appreciate some input u guys...

Heat Transfer and Calorimetry

A 50 g Aluminum calorimeter contains 95 g of a mixture of water and ice at 0 degree Celsius. When 100 g of Aluminum, which has been heated in a steam jacket to 100 degree Celsius, is dropped into the mixture, the temperature rises to 5 degree Celsius. Find the mass of ice originally present in the mixture if the specific heat capacity of aluminum is 0.22 cal/g*C
 
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How about you show your work. If you are completely lost on how to begin this problem, and thus have no work to show, then you should look up the heat/temperature change equations and the heat/phase change equations. Also remember the conservation of energy laws - heat gained equals heat lossed.
 

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