How Much K2SO4 Solution is Needed for a Specific Potassium Ion Concentration?

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To prepare a 450.0 mL solution with a potassium ion concentration of 145 ppm, the density of the solution is 1.01 g/mL, and the concentration of K2SO4 is 0.728 M. The calculation involves determining the total mass of potassium needed and then converting that mass into the volume of K2SO4 solution required. The process includes applying mass conservation principles to find the necessary volume of the starting K2SO4 solution. The final goal is to ensure the solution meets the specified potassium ion concentration. Accurate calculations are essential for achieving the desired concentration.
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Homework Statement


Want to prepare 450.0 mL of a 145 ppm K + ion solution. density of solution is 1.01 g/mL. solution is .728 M in K2SO4. How many mL of the K2SO4 solution need to use?


Homework Equations





The Attempt at a Solution



(.728 mol/L K2SO4 )(1.01g/mL)(450.0 mL)

i don't know what to do next...help?
 
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This is a simple mass conservation.

How much potassium will be present in the final solution?

What volume of the starting solution contains this amount of potassium?
 
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