How much of a head start does B need to win the race?

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In a race of 50 meters, runner A, moving at 5 m/s, will win against runner B, who runs at 3 m/s. To determine how much of a head start B needs to win, calculations show that B requires a minimum head start of 20 meters. This is derived from the equations of motion for both runners, where the time taken to complete the race is the same for both. By solving the equations, it is confirmed that with a 20-meter head start, B can finish the race simultaneously with A. Therefore, B needs at least a 20-meter head start to win.
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Hey all. Simple problem here. 2 people are running at 2 different speeds in a race 50m long (A at 5 m/s B at 3 m/s), A is clearly going to win, How much of a head start would B need to win?
(This isn't a homework problem I'm just wondering how long I have to wait for my movie to buffer before I should start watching it.)
 
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Min 20 metres.
 
Min?? Working out?
 
Minimum of 20 metres.
 
let the headstart be denoted by' x' and time taken to complete the race be 't'. Note that time will be same for A and B. Now, using the fact that
Distance traveled = Speed* time, we have
For A, 50= 5*t
For B, 50=x + 3*t
Solve these to get x=20, t=10
 
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