How Much Power is Needed to Lift 89 Skiers Up a Slope?

  • Thread starter Thread starter jfleury45
  • Start date Start date
  • Tags Tags
    Hill Lift Power
AI Thread Summary
To lift 89 skiers up a 600 m slope inclined at 15° at a speed of 2.5 m/s, the required motor power must account for gravitational and frictional forces. The normal force calculated is 615.923 N, leading to a frictional force of 36.955 N. The discussion seeks to determine the work done by friction and any additional forces acting on the skiers. Understanding these forces is crucial for calculating the total power needed for the T-bar tow. The conversation emphasizes the importance of applying physics equations to solve for the required motor power effectively.
jfleury45
Messages
2
Reaction score
0
1. A T-bar tow is required to pull 89 skiers up a 600 m slope inclined at 15° above horizontal at a speed of 2.5 m/s. The coefficient of kinetic friction is 0.06. Find the motor power required if the mass of the average skier is 65 kg.




2. w=F*d
P=F*v




3. I found the normal force to be 615.923 N I then found the frictonal force to be 36.955N. Where do i go from here?
 
Physics news on Phys.org
If you know the frictional force, how much work does it do on the skier? Are there any other forces doing work on the skier?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top