How much power is the customer receiving?

  • Thread starter Thread starter mike_302
  • Start date Start date
  • Tags Tags
    Electricity Power
AI Thread Summary
The discussion revolves around calculating the voltage and power received by a customer from an electric utility company. The voltage at the customer's house is determined to be 110 V for a load current of 110 A. The power received by the customer can be calculated using the formula P=V*I, where V is the voltage at the house and I is the load current. Participants are attempting to solve for power but are encountering difficulties with the voltage values. The focus remains on accurately determining the power based on the provided voltage and current.
mike_302
Messages
102
Reaction score
0

Homework Statement



8.
An electric utility company supplies a customer's house from the main power lines (115 V) with two copper wires, each of which is 53.6 m long and has a resistance of 0.125 Ω per 294 m. Calculate the voltage at the customer's house for a load current of 110 A.

Correct : 1.10E+02 V

9. [1 point, 10 tries]
For this load current, calculate the power that the customer is receiving.

?




Homework Equations



P=V*I ?

The Attempt at a Solution



I tried subbing in voltage at the house, voltage before the power lines (so 112.5 and 115 ) and these don't work...
 
Physics news on Phys.org
I would take the voltage at the customer's house that you already calculated mutiplied with the load current.
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Voltage Drop in Parallel Receptacle Wiring
Replies
9
Views
2K
Measurement technology textbook problems
Replies
1
Views
598
Measurement technology textbook problems
Replies
2
Views
484
Question about complex power in three phase circuits
Replies
2
Views
3K
Long distance electrical transmission efficiency
Replies
2
Views
2K
Solving Current & Power in 4 & 3 Wire Circuits
Replies
9
Views
2K
Power loss when fan is connected; finding current
Replies
1
Views
1K
Voltage, real reactive power question
Replies
4
Views
2K
Optimizing Voltage for Power Transmission Efficiency
Replies
4
Views
4K
Solving Power Transmission Homework for Small Town | 1.00MW @ 35km
Replies
6
Views
1K

Hot Threads

Recent Insights

Back
Top