How Much Space Does 0.736 kg of Oxygen Occupy at 1°C and 105 Pa?

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Homework Help Overview

The problem involves calculating the volume occupied by 0.736 kg of molecular oxygen at a specified pressure and temperature, utilizing the ideal gas law.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the number of moles of oxygen and the application of the ideal gas law. There is uncertainty regarding the correct molar mass and the method for calculating the number of moles.

Discussion Status

Some participants have provided clarifications regarding the molar mass of oxygen and the calculation of moles, while others are still seeking confirmation on their understanding of the process.

Contextual Notes

There is a noted confusion about the conversion between mass and moles, as well as the correct application of the ideal gas law in this context.

cstout
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Homework Statement


A mass of 0.736 kg of molecular oxygen is contained in a cylinder at a pressure of 1.0 × 105 Pa and a temperature of 1°C. What volume does the gas occupy?


Homework Equations



PV=nRT

V=nRT/P

The Attempt at a Solution




n=(.736)(1000)/16 = 46


V = (46)(8.31)(274.15)/(1x10^5)

where n = 46
R = 8.31 J/K/mol
T = 274.15k
P = 1x10^5

but that is not the correct answer, what am i doing wrong??
 
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Molecular oxygen is 0_2, two atoms of oxygen per molecule. That makes the molar mass 32g.
 
so would i multiply the mass of .736(1000)32 to find the n, or basically i still am unsure of finding the n
 
Multiply? You divided before and that was correct. One mole of O2 has mass 32g. So how many moles is .736kg?
 
ahh..thanks, i got it now
 

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