How Much Space Does 0.736 kg of Oxygen Occupy at 1°C and 105 Pa?

AI Thread Summary
To determine the volume occupied by 0.736 kg of molecular oxygen at 1°C and 105 Pa, the ideal gas law equation PV=nRT is used. The number of moles (n) is calculated using the correct molar mass of oxygen, which is 32 g/mol, leading to n = 23. The volume (V) can then be calculated using the rearranged equation V = nRT/P, substituting in the values for R, T, and P. The initial calculation was incorrect due to an error in determining the number of moles. The correct approach clarified that the mass should be converted properly to find the number of moles before calculating the volume.
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Homework Statement


A mass of 0.736 kg of molecular oxygen is contained in a cylinder at a pressure of 1.0 × 105 Pa and a temperature of 1°C. What volume does the gas occupy?


Homework Equations



PV=nRT

V=nRT/P

The Attempt at a Solution




n=(.736)(1000)/16 = 46


V = (46)(8.31)(274.15)/(1x10^5)

where n = 46
R = 8.31 J/K/mol
T = 274.15k
P = 1x10^5

but that is not the correct answer, what am i doing wrong??
 
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Molecular oxygen is 0_2, two atoms of oxygen per molecule. That makes the molar mass 32g.
 
so would i multiply the mass of .736(1000)32 to find the n, or basically i still am unsure of finding the n
 
Multiply? You divided before and that was correct. One mole of O2 has mass 32g. So how many moles is .736kg?
 
ahh..thanks, i got it now
 

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