How Much Steam Is Needed to Heat Water from 24°C to 90°C?

AI Thread Summary
To heat 100 grams of water from 24°C to 90°C, the mass of steam required is calculated to be 12 grams. The heat released by the steam as it condenses is 540m, and the heat released by the condensed water cooling from 100°C to 90°C is 10m, totaling 550m. The heat needed to raise the water's temperature is 6600 calories. By equating the total heat released to the heat required, the solution confirms that 12 grams of steam is sufficient. The calculation appears to be correct.
Jahnavi
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Homework Statement



The temperature of 100 gm of water is to be raised from 24°C to 90°C by adding steam to it .Calculate the mass of the steam required for this purpose .

Homework Equations



Latent heat of vaporisation of steam = 540 Cal/g

The Attempt at a Solution


[/B]
Let 'm' be the mass of steam added.

Heat released by steam as it condenses into
water = 540m

Heat released by condensed water as it moves
from 100°C to 90°C = mx1x10 = 10m

Total heat released = 540m+10m= 550m

Heat required by 100gm water to raise its temp from
24°C to 90°C = 100x1x66

Equating the two , 550m = 6600

m = 12gm

Is it correct ?

 
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Jahnavi said:

Homework Statement



The temperature of 100 gm of water is to be raised from 24°C to 90°C by adding steam to it .Calculate the mass of the steam required for this purpose .

Homework Equations



Latent heat of vaporisation of steam = 540 Cal/g

The Attempt at a Solution


[/B]
Let 'm' be the mass of steam added.

Heat released by steam as it condenses into
water = 540m

Heat released by condensed water as it moves
from 100°C to 90°C = mx1x10 = 10m

Total heat released = 540m+10m= 550m

Heat required by 100gm water to raise its temp from
24°C to 90°C = 100x1x66

Equating the two , 550m = 6600

m = 12gm

Is it correct ?
Looks good.
 
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