How much time does an object use to travel.

AI Thread Summary
To determine the time an object takes to travel 12 meters down a plane with a constant acceleration of 1 m/s² and an initial velocity of 5 m/s, the relevant equation is S = V₀*t + 1/2*a*t². The discussion highlights the need to rearrange this equation into a standard quadratic form, Ax² + Bx + C = 0, to solve for time. Participants emphasize the importance of recognizing the equation's structure and applying the quadratic formula to find the roots. There is also a side conversation about the nuances of language in math problems, particularly for non-native speakers. Overall, the focus is on applying the quadratic equation to solve for time in the given scenario.
Nerikk
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Homework Statement


How much time does the object use to travel 12m down a plane. The object has a constant acceleration of 1m/s2 and the starting velocity is 5m/s.

Homework Equations


S=V(starting velocity)*t+1/2*a*t2

The Attempt at a Solution


Here I struggle with changing the formula. I could just leave both t's on the left side and then use square root. But I have a slight feeling that this is not right.
 
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I could just leave both t's on the left side and then use square root. But I have a slight feeling that this is not right.
Very close - for that to work, the LHS needs to be a complete square.

Hint: quadratic equation

Aside:
I'm intrigued by the wording. Is time the sort of thing that gets used up by objects ... you know, like a car uses petrol?
Probably the question wants to know how much time is taken or occupied by an activity.
 
Yea, it's quite hard to word yourself correctly in another language. Especially in math. But I will check out quadratic equation! Thank you!
 
Oh it was a translation?! Well done - I couldn't tell. I wondered if maybe you just had a new-age physics teacher ;)
Since English is a second language ... I'll say a bit more.
The equation you are trying to solve can be put in form: ##At^2+Bt+C=0## - do so: A, B, and C, may be made of several variables.
You should recognize that as the equation for the roots of a parabola... you should know an equation to solve that. $$t\in \frac{-B\pm\sqrt{B^2-4AC}}{2A}$$
 
I think I need some more help on that one. First of all how do I achieve 0 on the right side of the equation. Second how do I determine the variables?

And thank you for all your help! It seems like I lack some fundamentals in physics, heh...
 
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