B How much time it takes to walk a certain distance?

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The discussion centers on how slope affects pedestrian walking speed, with a standard speed of 1.4 meters/second typically assumed for flat terrain. It is noted that walking uphill requires more energy, resulting in a slower pace, while downhill walking allows for a faster speed due to gravity's assistance. A proposed formula, V(α) = 1.4 m/s / (1 + 0.3 tan(α)), suggests that at a 20-degree slope, speed decreases by about 10%. However, the accuracy of this formula is questioned, as individual factors like fitness and gait can significantly alter actual walking speed on slopes. Ultimately, empirical data is necessary for precise calculations, as theoretical models may not apply universally.
george95
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Hello,
I have one issue: I would like to know how much time will it take a pedestrian to walk certain distance (based on its movement speed), but taken into account the slope that his walking path takes?

I checked a number of sources and most of them quote the speed of an adult, healthy, pedestrian (I assume an average of male and female values) to be:
1.4 meters/second. Which is 84 meters/minute or around 275 feet/minute.

However, can it be that this 1.4m/s is actually the value in case the pedestrian is walking on a relatively flat terrain? What happens he is walking on a sloped terrain, of a certain angle!
For example, a pedestrian is walking on a terrain which has a constant slope angle of 20 degrees. How does those 20 degrees reduce the 1.4 meters/second walking speed?

I would be grateful for any kind of reply.
Thank you in advance!
 
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If the person is walking uphill they will have to expend additional energy (because of working against gravity).
So assuming they don't deliberately speed up to compensate, but keep walking at a comfortable rate,, that rate will be slower than on flat ground.
Conversely they need less energy to travel downhill, so they will move faster without any additional effort, in that case gravity is assisting them.
 
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Thank you for the quick reply rootone!
rootone said:
So assuming they don't deliberately speed up to compensate, but keep walking at a comfortable rate,, that rate will be slower than on flat ground.
Yes, but how much slower in relation to the angle of the slope?
 
That will probably be very hard data to come by. This isn't a question that can be answered with a convenient formula, it has to be established empirically.
 
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Thank you for the reply rumborak.
I would accept empirically derived formulas as well!
 
What you *might* be able to do, with a bit of handwaving, is to say "on flat ground a person burns so many calories, i.e. Joules per distance covered. Now, let's assume on a slope this person tries to keep their heart rate the same as on flat ground, but part of that energy expenditure now goes to lifting the body to a higher altitude, I.e. increasing the potential energy". If you work that backwards, you might get a value for the speed that keeps the overall energy expenditure the same.
 
FYI, because it's horrendous weather in Boston and I'm bored, after a bit of calculations I got to the formula:

$$V(α) = \frac {1.4 m/s} {1+0.3 \tan {α}}$$

User at your own peril.

EDIT: So, at your asked 20 degrees, the speed would be 10% slower. Honestly, doesn't sound right, but I think that's because at 20 degrees already a lot of other factors come into play like your gait changing etc. Humans are evolutionarily optimized to burn little energy on flat ground. When it's no longer flat, less efficient muscle come into play that burn more energy.
 
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Yes, the exact figure will be highly dependent on the individual's body frame, their metabolism, overall fitness, whether they have eaten recently, and a whole load more.
While you could come up with a formula for an idealized average person, that person most likely does not exist in reality,
so whatever theoretical formula you apply, in practice you'll have very wide error margins if testing it with actual people.
 
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First, 20 degrees is a huge angle! This is about what it looks like:

MNemeth_20160725_DSCF0308.jpg


Second, if you ever are walking with a group of friends and hit a hill, you will immediately notice that you start to disperse until an effort is made to get back together. That alone says there is no universal formula applicable to all people. If there were, you would stay together.
 
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  • #10
george95 said:
Hello,
I have one issue: I would like to know how much time will it take a pedestrian to walk certain distance (based on its movement speed), but taken into account the slope that his walking path takes?

I checked a number of sources and most of them quote the speed of an adult, healthy, pedestrian (I assume an average of male and female values) to be:
1.4 meters/second. Which is 84 meters/minute or around 275 feet/minute.

However, can it be that this 1.4m/s is actually the value in case the pedestrian is walking on a relatively flat terrain? What happens he is walking on a sloped terrain, of a certain angle!
For example, a pedestrian is walking on a terrain which has a constant slope angle of 20 degrees. How does those 20 degrees reduce the 1.4 meters/second walking speed?

I would be grateful for any kind of reply.
Thank you in advance!

What you need is Naismith's rule:

https://en.wikipedia.org/wiki/Naismith's_rule
 
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  • #11
Thank you for all the replies!

rumborak said:
FYI, because it's horrendous weather in Boston and I'm bored, after a bit of calculations I got to the formula:

$$V(α) = \frac {1.4 m/s} {1+0.3 \tan {α}}$$

User at your own peril.

EDIT: So, at your asked 20 degrees, the speed would be 10% slower. Honestly, doesn't sound right, but I think that's because at 20 degrees already a lot of other factors come into play like your gait changing etc. Humans are evolutionarily optimized to burn little energy on flat ground. When it's no longer flat, less efficient muscle come into play that burn more energy.

Thank you Rumborak! What is the source of your formula?
 
  • #12
PeroK said:
What you need is Naismith's rule:https://en.wikipedia.org/wiki/Naismith's_rule
That is, 7.92 units of distance are equivalent to 1 unit of climb.
Rules of thumb like this are often handy.
While there is no theory to explain it, it's a statistic that satisfies most observations.
 
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  • #13
Thank you once again for the useful replies PeroK and rootone.

rumborak said:
FYI, because it's horrendous weather in Boston and I'm bored, after a bit of calculations I got to the formula:

$$V(α) = \frac {1.4 m/s} {1+0.3 \tan {α}}$$

User at your own peril.

EDIT: So, at your asked 20 degrees, the speed would be 10% slower. Honestly, doesn't sound right, but I think that's because at 20 degrees already a lot of other factors come into play like your gait changing etc. Humans are evolutionarily optimized to burn little energy on flat ground. When it's no longer flat, less efficient muscle come into play that burn more energy.

@rumborak what is the source of your formula? Where does it come from?
 
  • #14
That formula really just comes from the assumptions I made in the preceding post to that. I think as is obvious, it's pretty off since it totally disagrees with Naismith's rule. It was really little more than a algebra exercise.
 
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  • #15
Thank you once again for the help Rumborak.
 
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