How Much Weight Must Block C Have to Prevent Block A from Sliding?

AI Thread Summary
To prevent block A from sliding, block C must weigh at least 20 N, considering the static friction coefficient of 0.20. The forces acting on block A include its weight and the tension from block B, which is 25 N. If block C is removed, the acceleration of block A is calculated to be 2 m/s², factoring in the kinetic friction coefficient of 0.15. The discussion emphasizes the importance of understanding the forces and conditions for equilibrium in this scenario. Proper calculations are essential for determining the necessary weight of block C and the resulting acceleration of block A.
djester555
Messages
10
Reaction score
0
blocks A and B have weights of 45 N and 25 N, respectively.



block A is sitting on a table and block B is attached to block A by a piece of string on a frictionless pulley and block B is hanging off the table. also block C is on top of block A



Figure 6-48
(a) Determine the minimum weight of block C to keep A from sliding if µstat between A and the table is 0.20.

(b) Block C suddenly is lifted off A. What is the acceleration of block A if µkin between A and the table is 0.15?
2 m/s2




A)
block a = 45n
block b = 25n
block c = 45 -25
block C = 20N i don't think this is right

B) can't solve without part A
 
Physics news on Phys.org
Find out the forces acting on A and C. Similarly find out the force acting on B. Find the acceleration of the system. Find the condition for the equilibrium.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Forces/Dynamics: A block sliding on a plate
Replies
45
Views
7K
Pushing down on a block at an angle on a horizontal table with friction
Replies
7
Views
2K
How Does Friction Affect Acceleration on an Incline?
Replies
19
Views
3K
Frictional force acting between 2 stacked blocks
Replies
2
Views
2K
Two Blocks and a Pulley Friction Problem
Replies
2
Views
4K
Case when there is no normal force in spite of contact
Replies
28
Views
3K
How Do You Calculate Forces in a Multi-Block System with Friction?
Replies
7
Views
3K
The tension in the cord in this system
Replies
7
Views
2K
Why do both Block A and B have a zero acceleration in this scenario?
Replies
11
Views
2K
How Do You Calculate the Force Needed to Prevent a Block from Sliding on a Wall?
Replies
1
Views
2K

Hot Threads

Recent Insights

Back
Top