zaga04
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Homework Statement
Heat input of an engine is 1330 J/s at 375°C and heat output is 800 J/s.
Each second, how much work is done in the process?
Homework Equations
QL/QH=1-e
The Attempt at a Solution
QL=(1-e)QH
QH=W/e
W=average of 1330 and 800 which is 1065J
QH=1065J/.40 (e was calculated in part A, which I don't need help on).
= 2.6625kJ
QL=(1-.40)2.6625kJ
QL=1.6kJ/s or 1.6kW
I followed an example in my textbook, the part I am confused on is how to get W, I just took the average of the two that were given.