How much work is done by the engine?

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The engine has a heat input of 1330 J/s and a heat output of 800 J/s, leading to a calculated work output of 1065 J per second. The efficiency of the engine is determined to be 0.40, which is used to derive the heat output and rejected heat values. By applying the conservation of energy principle, the relationship between heat input, work done, and heat rejected is established. The rejected heat is calculated as 1.6 kW. Overall, the discussion emphasizes the conversion of heat energy into work while accounting for energy losses.
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Homework Statement


Heat input of an engine is 1330 J/s at 375°C and heat output is 800 J/s.

Each second, how much work is done in the process?

Homework Equations


QL/QH=1-e

The Attempt at a Solution


QL=(1-e)QH

QH=W/e

W=average of 1330 and 800 which is 1065J

QH=1065J/.40 (e was calculated in part A, which I don't need help on).
= 2.6625kJ

QL=(1-.40)2.6625kJ
QL=1.6kJ/s or 1.6kW

I followed an example in my textbook, the part I am confused on is how to get W, I just took the average of the two that were given.
 
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An engine converts heat to work.


So heat is input to the engine, the engine does work and rejects some heat.

If we apply conservation of energy we get.


Heat input=Work done + heat rejected
 
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