How much work is done by the thrusters on a shuttle changing distances of orbit

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A 2000kg lunar lander needs to move from a 40km orbit to a 500km orbit to rendezvous with a mothership. The work done by the thrusters is calculated using the difference in total energy between the two orbits. Initial calculations yielded results around 9.91*10^9 joules, but the correct approach involved converting distances from kilometers to meters. The final solution required integrating the gravitational force over the distance to determine the work done by non-conservative forces. The discussion highlights the importance of unit conversion and understanding energy in orbital mechanics.
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Homework Statement



a 2000kg lunar lander is in orbit 40km above the surface of the moon. it needs to move out to a 500km orbit in oder to link up with a mothership that will take the astronauts home. it wants the answer in joules

Homework Equations


??E2-E1=Work done by non conservative forces


The Attempt at a Solution


I get answers like 9.91*10^9 joules or negative 9.91*10^9

i thought that Total energy in an orbit=0 so i solved E(@40km)=mv1^2-GMm/r1=2000(v1^2-GM/40000+Rmoon)
 
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Does the topic happen to be work/energy (as in "potential energy")?

If so maybe m*g_moon(h2-h1)... is worth thinking about
 
Ooops - the distances are km! (I was thinking meters).

You'd probably need to integrate f(r)dr [force as a function of distance times incremental change in distance to center of moon - i.e. work] from (40000+R_moon) to (500000+R_moon), where f(r)=Gm1m2/r^2

m1=mass of moon
m2=mass of lander
R=radius of moon
 
Thanks for the help but i finally figured it out.

I had to take the total energy of the second orbit minus the total energy of the first orbit to get the work done by non conservative forces aka the thrusters. Thanks for your assistance though especially about changing it to meters from km
 
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