How much work is done on a bicyclist and her bike when coasting up a hill?

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AI Thread Summary
The discussion focuses on calculating the work done on a bicyclist and her bike while coasting up a hill. The initial and final speeds are given as 7.10 m/s and 6.00 m/s, respectively, with a combined mass of 67.6 kg. The attempt to find the work done involves using the kinetic energy formula, but the calculations yield -487 J, which is incorrect. The user seeks clarification on the correct mathematical approach to derive the right answer. The conversation emphasizes the importance of correctly applying the kinetic energy equation to solve the problem accurately.
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Homework Statement



Coasting along at 7.10 m/s, a 60.0 kg bicyclist on a 7.60 kg bicycle encounters a small hill. If the speed of the bicyclist is 6.00 m/s at the top of the hill, how much work was done on the bicyclist and her bike?


Homework Equations



KEf-KEi=W
.5mvi^2-.5mvf^2
kg*m^2*s^-2
m=60kg+7.60kg
v=m/s


The Attempt at a Solution



I tried finding the loss in KE and having that be the work done. I get

.5mVf^2 -.5mVi^2
.5*67.6kg*36 - .5*67.6kg*50.41

I get -487 J and it tells me this is the wrong answer? What did I do wrong?
 
Last edited:
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Please write out the whole equations. Include the mass and the units.
 
I tried finding the loss in KE and having that be the work done. I get

.5m(Vf-Vi)^2 and I get -487 J and it tells me this is the wrong answer? What did I do wrong?

Your final expression is incorrect mathematically.
 
I relized i posted that wrong but the answer comes out to -487 the right way but that's the wrong answer. I edited and wrote everything out.
 
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