- #1
Hypnos_16
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Homework Statement
A 69.7-kg skier coasts up a snow-covered hill that makes an angle of 26.8° with the horizontal. The initial speed of the skier is 6.16 m/s. After coasting 1.98 m up the slope, the skier has a speed of 3.95 m/s. Calculate the work done by the kinetic frictional force that acts on the skis.
m = 69.7
Theta = 26.8 degrees
v1 = 6.16 m/s
d = 1.98m
v2 = 3.95 m/s
Homework Equations
I've found the total work done by using Wnc = Ef - Ei
but that gives me the wok of all the forces and i don't know how to pinpoint just the force done by friction
The Attempt at a Solution
∑W = Ef - Ei
∑W = (1/2mv^2) + (mgh) - (1/2mv^2) + (mgh)
∑W = (34.9)(3.95^2) + (69.7)(9.81)(1.98) - (34.9)(6.16^2) + (69.7)(9.81)(0)
∑W = (544) + (1353.8) - (1324) + (0)
∑W = 1897.8 - 1324
∑W = 573.8 J