How much work is done on the mass by the tension

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The work done on the mass by the tension of the string during one revolution is zero, as the force exerted by the tension is orthogonal to the direction of motion. This aligns with the work-energy theorem, which states that if no work is done, there is no change in kinetic energy. The tension maintains the circular motion without contributing to the work done. The discussion highlights the relationship between force direction and work in circular motion. Understanding these principles is crucial for applying the work-energy theorem effectively.
UNknown 2010
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. You swing a 55-g mass on the end of a 0.75-m
string around your head in a nearly horizontal circle
at constant speed, as shown in Figure 11-16.
a. How much work is done on the mass by the
tension of the string in one revolution?
b. Is your answer to part a in agreement with
the work-energy theorem? Explain.
my answer
a-the work is zero because the distance and Force are Orthogonal
b- I do not have answer for this question
 
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UNknown 2010 said:
a-the work is zero because the distance and Force are Orthogonal
Good.
b- I do not have answer for this question
What does the work-energy theorem say?
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
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