How much work is done. Physics problem

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To find the potential midway between two identical +38 µC charges placed 41 cm apart, the potential can be calculated using the formula V = k * q / r, where k is Coulomb's constant. The work done to move a 0.40 µC charge from the midpoint to a point 10 cm closer to either charge involves calculating the change in potential energy, ΔV, and then multiplying by the charge. The equations provided, F = k * qq / r and V = m/q, are relevant for solving the problem. The user expresses uncertainty about the starting point for the calculations but suggests using the potential difference to determine work. The discussion emphasizes the need to apply the correct physics principles to solve the problem effectively.
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Homework Statement



1. A +38 uC charge is place @ 41cm from an identical +38uC. If assuming the potential identity is 0. what's the potential midway btw the 2 charges?
2. How much work is done to move a 0.40 uC charge from a point midway between the charge to a point 10 cm closer to either of the charges?

Homework Equations



V= m/q ?
F= Ke qq/r

The Attempt at a Solution


Not sure where to start but...
8.99e-19(38e-6)(q3)/(.041m-x )^2
8.99e-19(38e-6)(q3)/(x )^2
 
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Simply calculate the ΔV because that times q is your work.
 


so i used V= Ke q/r?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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