How much work is done when moving an object from x_1 to x_2?

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To calculate the work done by the hand in moving an object from x_1 to x_2 against an attractive force F_x = -k/x², one must consider the work done against this force. The work done by the hand is equal to the change in potential energy, which is k/x_1 - k/x_2 after integration. The confusion arises from differentiating between the work done by the external force (the hand) and the work done by the attractive force. Clarification on these concepts is essential for solving similar problems. Understanding the relationship between force, distance, and work is crucial for completing the assignment successfully.
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Please help with this question...whatever answer I put in is wrong.

An object is attracted toward the origin with a force given by
F_x = - k / x^{2}. (Gravitational and electrical forces have this distance dependence.)

The only other force acting on the object is a force that you exert with your hand to move the object slowly from x_1 to x_2. How much work do you do?

I know the work of the force of the object is k/x_2 - k/x_1, after you integrate it. But this is the work done by the force exerted with your hand and I'm getting confused. Any help would be very much appreciated. :)
 
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We recently had a question that seems to be exactly the same. Have a look at it in this thread. Hope that it helps you.
 
Yup...the person must be doing the same unit of study as me...lol. Stupid assignment...thank you so much. :)
 

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