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milla7
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Homework Statement
Question
A 7.6 kg body is at rest on a frictionless horizontal air track when a constant horizontal force F with arrow acting in the positive direction of an x-axis along the track is applied to the body. A stroboscopic graph of the position of the body as it slides to the right is shown in the figure. The force F with arrow is applied to the body at t = 0, and the graph records the position of the body at 0.50 s intervals. How much work is done on the body by the applied force F with arrow between t = 0 and t = 0.5 s?
Homework Equations
x=vot +1/2at^2
v=at
m/2(Vf^2-Vi^2)
The Attempt at a Solution
When I work the problem I get 0.152 Joules.
.8 = 1/2 a(2.0)^2
a=0.4
v=0.4(0.5)
v=0.2
1/2(7.6kg)(.2^2)= 0.152J.
I work it this way and I have no idea why it is wrong. The answer is supposed to be 0.0973.
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