How Much Work is Needed to Pull a Skier Up a Slope?

  • Thread starter Thread starter kmart47
  • Start date Start date
  • Tags Tags
    Work Work problem
AI Thread Summary
To calculate the work required to pull a skier of mass 72.9 kg up a 63.5 m slope at a constant speed of 2 m/s², the gravitational potential energy change must be determined. The energy change is calculated using the formula: work = mass × gravity × height. The height can be found using the sine of the slope angle, leading to a height of approximately 21.5 m. This energy must come from the motor-driven cable, which does the work against gravity, resulting in a total work requirement of approximately 1,540 J.
kmart47
Messages
1
Reaction score
0
a skier of mass 72.9 kg is pulled up a slope by a motor-driven cable. The acceleration due to gravity is 9.81 m/seconds squared. How much work is required to pull the skier 63.5 m up a 34 degree slope (assumed to be frictionless) at a constant speed of 2 m/seconds squared. Answer in units of J.



HELP me out please
 
Physics news on Phys.org
calculate the change in gravitational energy.
where must this energy come from?
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Skiing Up a Slope: Solving Work & Power Requirements
Replies
9
Views
2K
Work and Energy on a Slope - How Does a Block Move Up with Zero Net Work?
Replies
3
Views
2K
Work Pulley Problem with constant speed
Replies
2
Views
967
Power Needed to Pull Skier Up Slope
Replies
1
Views
2K
How Much Work Does It Take to Pull a Skier Up a Slope?
Replies
1
Views
2K
Solving Work & Forces Problems: Alpine Rescue Team
Replies
1
Views
2K
Solve a Skier Work Physics Problem on a 37.2° Slope – No Friction
Replies
3
Views
2K
What is the average force required to pull the rope?
Replies
36
Views
6K
Work and energy of an object on a ice slope
Replies
7
Views
1K
Dynamics Skier on a Slope Problem
Replies
9
Views
5K

Hot Threads

Recent Insights

Back
Top