How much work to move a charge?

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The discussion centers on calculating the work done by a 12-V battery in moving 2 mC of charge through a circuit. The formula for work is established as W = qV, where W is work, q is charge, and V is voltage. The calculated work amounts to 0.024 J, indicating that the answer is C. While some participants suggest that the type of bulb could affect the circuit, the fundamental calculation remains consistent regardless of the bulb's characteristics. Understanding the relationship between voltage, charge, and work is crucial for solving similar problems.
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I was wondering if anyone could tell me the formula for work?

I have to answer this question:

How much work does a 12-V battery do in pushing 2mC of charge through a circuit containing 1 light bulb.
A. .006 J
B. .012 J
C. .024 J
D. The answer depends on the type of bulb in the circuit.

Well either there is a formula I don't know, or the choice d is right. I was thinking about d, that it depends on the bulb. Because if the bulb would some how provide resistance or stop the circuit that could prevent the charge from moving...So that's a possibility, and then if there's some formula I don't know, then I need that to solve for an answer.

thanks!
 
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well work is the potential energy difference - and in this case its qV
 
A definition of potential difference (or voltage) is work done per unit charge; V = \frac{W}{q}. Re-arranging this gives W = qV, as fargoth said. This definition of potential difference is useful to remember.
 
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