How Nuclear test are done underground

  • Thread starter Thread starter r.vittalkiran
  • Start date Start date
  • Tags Tags
    Nuclear
r.vittalkiran
Messages
16
Reaction score
0
Many countries have been found building Nuclear weapons,
I want to know how Nuclear test are done underground, and doesn't it cause any damage?
Many countries do test Missiles(firing them towards sea), are they loaded ones/ unloaded missiles?

WONT NUCLEAR TEST'S CAUSE DAMAGE​
 
Physics news on Phys.org
If a nuclear test is conducted sufficiently deep underground, only a small amount of radiation is released to the environment. An underground test can create a cavity up to several hundred meters in diameter. Soon after the test, the cavity collapses in on itself which may cause a small surface crater as well, depending on the depth. Nuclear bombs are not powerful enough or detonated deep enough to cause earthquakes or any other significant geological effect.

Ballistic missile tests performed by North Korea and Iran are not loaded with warheads, they are testing the functionality of the launch and guidance system.
 
Do they always collapse? I think I saw a show on TV once where they sent a crew down into one of these cavities, decades after the test, of course.

Maybe I'm thinking of something else.
 
I don't know. A cavity from a low yield device at a relatively shallow depth might remain intact.
 
Thread 'Why is there such a difference between the total cross-section data? (simulation vs. experiment)'
Well, I'm simulating a neutron-proton scattering phase shift. The equation that I solve numerically is the Phase function method and is $$ \frac{d}{dr}[\delta_{i+1}] = \frac{2\mu}{\hbar^2}\frac{V(r)}{k^2}\sin(kr + \delta_i)$$ ##\delta_i## is the phase shift for triplet and singlet state, ##\mu## is the reduced mass for neutron-proton, ##k=\sqrt{2\mu E_{cm}/\hbar^2}## is the wave number and ##V(r)## is the potential of interaction like Yukawa, Wood-Saxon, Square well potential, etc. I first...
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top