From the article "Which Way To Mars?. Trajectory Analysis. by Kelsey B. Lynn" that I have read, it states that the Hohmann Trajectory at earth,V1=32.76km/s and the earth velocity,VE=29.82km/s,so the hyperbolic excess velocity,VH=[V1-VE]=2.940km/s.All these parameters lead to the calculation of the total velocity needed for launch from earth[know as the delta V].To launch from one of the earth'spoles,the delta V is a combination of VH[hyperbolic excess velocity] and VES[escape velocity from earth],that is delta V=[VH^2+VES^2]^.5 =11.6km/s. The value of VES=11.18KM/S,of course.What I would like to know is how the formula{deltaV=[VH^2+VES^2]^.5} is derived? Any help for explanation would be appreciated. Thanks a lot.(adsbygoogle = window.adsbygoogle || []).push({});

**Physics Forums - The Fusion of Science and Community**

# How the calculated total velocity derived ?

Have something to add?

- Similar discussions for: How the calculated total velocity derived ?

Loading...

**Physics Forums - The Fusion of Science and Community**