How the efficiency of transformer affects turn ratio

AI Thread Summary
The discussion centers on the relationship between transformer efficiency and turn ratio. It clarifies that the voltage ratio (Vp/Vs) equals the turns ratio (Np/Ns) only in an ideal transformer without losses. However, ohmic losses, including those from eddy currents and magnetic hysteresis, do affect efficiency and lead to energy loss. This loss results in a modification of the voltage ratio, indicating that real transformers do not achieve the ideal conditions described in textbooks. Overall, efficiency impacts the voltage ratio due to inherent losses in practical transformers.
mmssm
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A secondary textbook said that if there is no flux leakage,
Vp/Vs=Np/Ns, no matter what is the efficiency of the transformer. May I know will the ohmic loss and eddy current contribute to the loss and modify the voltage ratio? thanks!
 
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mmssm said:
A secondary textbook said that if there is no flux leakage,
Vp/Vs=Np/Ns, no matter what is the efficiency of the transformer. May I know will the ohmic loss and eddy current contribute to the loss and modify the voltage ratio? thanks!

That secondary book says , that power in equals power out in a transformer, so ,

Vp/Vs = Is/Ip = Np/Ns , only when the transformer is an ideal machine.

Ohmic loss is contributed due to eddy currents and magnetic hysteresis and in that case there will be flux leakage. So this will lead to energy loss and will modify the Vp/Vs ratio.
 
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