How to Balance a Seesaw with Three Children?

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To balance a seesaw with a 150N child and a 250N child at opposite ends, the third child weighing 180N must be positioned correctly based on torque calculations. The total torque must equal zero for balance, with clockwise and counterclockwise torques considered. The torque generated by the 150N child is 300 N·m, while the 250N child generates 500 N·m. The third child should sit closer to the 150N child to counterbalance the greater torque from the 250N child. Proper assignment of torque signs and understanding of distances are crucial for solving the problem effectively.
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A 150N child and a 250N child sit at opposite ends of a 4.0m seesaw pivoted at its center. Where should the third child whose weight is 180N sit in order to balance the seesaw?

Do you need to solve this problem or answer it where the 3rd child will be put
 
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Please show what you've tried.
What equation(s) do you think you're supposed to use?
 
TORQUE = LENGTH * FWboy
is it okay to assign clockwise and cclockwise to every number?
clockwise
TORQUE = 2.0m * 150N
TORQUEboy1 = 300 N * m
counterclockwise
TORQUEboy2 = 2.0m * 250N
TORQUEboy2 = 500N
waaaa I am so dumb
what now
 
Total torque must equal 0 to keep the seesaw from rotating.
You are using the correct formula, can you figure out what the "lenght"(/distance) should be for the 3rd boy for the torque to equal 0?
 
oh

Torqueboy1 + Torqueboy2 + Torqueboy3 = 0
300N.m + 500 N * m + 180 N * M<-(unknown) = 0

i know how but I've got a problem with Clockwise and C.Clockwise where can i assign them...

plss helpp...
thx
 
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You should draw a diagram, and think where the seesaw will rotate if only one boy is placed on eg. the left.
You can choose the sign (+/-) however you like, but all torque causing clockwise rotation must have the same sign and it must be opposite to the ones causing counter-clockwise rotation.

I'm extremely confused about your markings, what are N.m, N * M, <-(unknown) ?
 
oh its the Length of the third boy * Its Normal Force..
weighing 180N to balance the seesaw..

so i was just wondering if the third boy can be assigned at the CC or C rotation...?.. icant assign it as positive or negative
helpp..

thx again
 
Which way would the seesaw rotate if the 3rd boy wasnt placed there? To balance this rotation out, where should the 3rd boy be placed?
 
hmm......
3rd boy should be with the boy weighing 150N because it's lighter
 
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  • #10
Yes, correct, sort of. It's not because of the lighter weight, but because of the smaller torque.
 
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  • #11
yup i get it now thanks :)
 
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