# How to build high sensitivity+high voltage function gen

1. Dec 18, 2013

### EE4life

Hi all,

I am in need to create a system with which can output a AC signal of high voltage and also have good resolution at low voltages.

Currently, I am using a function generator with an 100X amplifier connected to a potentiometer. When I want to use low voltage I turn the potentiometer to a high resistance, and vice versa.

I want to use this equipment with automated control using labview to drive a piezo at high (off resonance) and low voltage (resonance). I would like for the resistance be changed simply using electronic switches.

I was thinking about using a MOSFET, but I do not think the voltage may be too large (100 volts) for a MOSFET.

Do you guys have any advice on my issue?

2. Dec 18, 2013

### Staff: Mentor

Welcome to the PF.

What frequency range do you need? I'm assuming that the load impedance is fairly high, right? Do you need 50 Ohm output impedance, or can you live with a higher output impedance? What is your definition of "good resolution"? If you based this generator on a 12 bit full scale DAC, would that give you the resolution you need?

3. Dec 18, 2013

### EE4life

The frequency range is 10 KHz-200 KHz. At resonance the load impedance is around 50 Ohms and at antiresonance the load impedance is around 50 KOhms. A higher output impedance is okay. The resolution should be within 1/100 of the voltage value at least, so I guess that is achievable in any case.

(approximate calculations)
To drive at antiresonance (high voltage), we need 100V. So with setting the function generator to 10 volts, X100,=1000V. The potentiometer needs to be at 5 KOhms.
For resonance, assuming we need around 1 volts drive, with the same setup, if we reduce the function generator to 1v, we get 100V out of the amplifier. Since the potentiometer (5 KOhm) is in series with the piezo device the piezo is driven at 1 volt.

In this example we have placed a large externally placed impedance load to make the voltage right. I would like to get around this somehow.

4. Dec 18, 2013

### Staff: Mentor

Instead of putting a resistance in series to alter the amplitude, why not just adjust the amplitude of the signal generator? Or even put a variable gain amplifier between the signal source and the load?

5. Dec 18, 2013

### EE4life

Variable gain amplifiers of this sort would be expensive given the large voltage and modest power. Adjusting the signal generator wont work because a it is difficult to get a 1V-150V output with only a 100m to 10V signal generator without the large series impedance. The max power need by the piezo is around 200mW.

6. Dec 18, 2013

### EE4life

Do you have a suggestion for the variable amplifier?

7. Dec 18, 2013

### Staff: Mentor

Can you say more about what you are trying to achieve with this test setup? It would seem that having a varialble output impedance for the waveform source would affect the results of the piezo testing. Is that not the case? What are you looking for in your piezo measurements?

Another alternative would be to use two different signal sources for the high-voltage and low-voltage measurements. You could switch between them using a relay, for example.

8. Dec 19, 2013

### Staff: Mentor

Last edited: Dec 19, 2013
9. Dec 19, 2013

### EE4life

I sweep the frequency (slowly) and then I will measure the impedance across the the piezo. I will measure the voltage across the piezodevice and I also am measuring the current, therefore I can measure impedance.

So, essentially I am making an hp analyzer, but I am using higher voltage. Also, using the labview program I am also doing constant current and constant electrical power frequency sweeps. With the impedance I am measuring the quality factor.

10. Dec 19, 2013

### Staff: Mentor

Are you measuring the phase of the impedance as well? An HP impedance analyzer measures complex impedance...

11. Dec 19, 2013

### EE4life

Yes, I am also measuring phase between the voltage and current. This would change with the pot resistance...wouldn't it?
-----
How much power can I get out the op amp? I think that is for a low power device. The people my lab before me are/were using something like (big box type amplifer) http://www.ferrodevices.com/1/297/files/Precision_200V_HighSpeed_Ex_A3.pdf
But, perhaps they were overdoing it because the current and demands are not very high, although the voltage might be.
-----
Anyways, a relay between two function generators seems like an easy and simple solution. Do you have a suggestion for a relay for my application?

Last edited: Dec 19, 2013
12. Dec 19, 2013

### vk6kro

If you drive an amplifier which has a gain of 100 with a 1 volt signal, you do not get 100 volts out, usually.

This is because the amplifier will give distorted output at a much lower voltage. Most amplifiers would not be capable of giving 100 volts peak to peak output.

If you drive it with 50 mV peak to peak, you might get 5 volts output, but, depending on the amplifier, driving it with much more than this will usually give output which is distorted and nowhere near 100 volts in amplitude.

If you just want to test a piezo device, place it in series with a 10k resistor across the output of a signal generator, and measure the voltage across the resistor with an oscilloscope as you vary the frequency of the signal generator.

You can observe the output of the signal generator with the oscilloscope at the same time. So, you can measure phase differences, if any, between input and output of the test setup.

You can also adjust the output of the signal generator so that it remains constant at different frequencies.

For convenience, you would place the resistor at the ground end of the series circuit. This allows you to connect an oscilloscope to it easily.

13. Dec 19, 2013

### EE4life

I am not clear on why are suggesting to test the voltage over the 10k resistor. I am measuring current using a current probe.

By the way, I want to make a clarification. The potentiometer is between the function generator and the amplifier, so it does not add to the impedance of the piezoelectric device. I have attached a crude picture of my setup. Again, I use the voltage and current to calculate impedance, from which I get the quality factor (from 3db bandwidth). I also calculate phase angle between the voltage and current to get the power.

#### Attached Files:

• ###### setup.png
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14. Dec 20, 2013

### vk6kro

If you apply a steady voltage across the series Piezo--resistor combination, then the piezo is protected from excess drive and the voltage across the resistor depends on the impedance of the piezo.

Some piezo devices are rugged, but most can be damaged by excess drive.

Doing it this way, you don't need current probes or extra amplifiers.
As mentioned above, signal generators have panel controls that control output amplitude. You don't need any external potentiometers.

15. Dec 20, 2013

### EE4life

Will the series resistor mess up the resonance characteristics of the piezo (typically we just measure a plate or disk of piezoelectric material, so it not really a actual device)?

At resonance the piezo impedance is between 30-100 Ohms (not kohms) and at antiresonance the impedance is around 50k. What I really want to find out is the impedance of the piezo across a frequency sweep from resonance to antiresonance.

16. Dec 20, 2013

### vk6kro

You can adjust the value of the resistor to suit your device. As long as you know the resistance of the resistor, you can calculate the resistance of your piezo sample.

Possibly, 1000 ohms would be better in your case. You can easily try it and do a frequency sweep.
Ideally, you should try to have results that are varying with frequency, not staying near zero volts or near the maximum voltage.

Watch to see if the voltage across the resistor stays in phase with the input voltage. If it doesn't, you will need to use vector diagrams to calculate the impedance of the sample.

I wouldn't expect the resistor to affect the resonance frequency much or at all. You can easily find out by trying different resistors as you approach resonance.

17. Dec 20, 2013

### meBigGuy

All this talk of series resistances and X100 gain amplifiers that distort is just confusing the issue.

The two circuits in NO's post (#8) will do this right. Using an input pot will give you whatever range you want.

Why wouldn't you just do it that way? Am I missing something?

18. Dec 20, 2013

### vk6kro

I don't know. Are you?

To measure the resonant frequency of a "piezo" you don't need to generate high voltages as the early posts suggested.
The voltage from a signal generator is adequate.
That is where the series resistor comes in.
You compare two impedances by putting them in series across a constant amplitude AC signal. Then measure the voltages across the two impedances.

I made the point that the average X100 amplifier will not generate hundreds of volts just by feeding it with a few volts of drive. More likely, it will generate about 10 volts of distorted output.

That seems fair comment.

19. Dec 21, 2013

### meBigGuy

I just re-read the OP. I assume you have a function generator and a separate 100X amplifier that already gives you the high voltage you need. Are you saying you need different output impedances to get the measurements you need, not just different drive voltages.

1. If yes, what range of impedences do you need and how many steps?

2. If no, why not a fixed output resistance and a pot on the input to the amplifier.

I'm still not clear what your specs are with respect to drive voltage and drive impedance.

20. Dec 21, 2013

### vk6kro

The OP was fairly garbled but it asked for a design of a suitable amplifier.

There was no description of the actual type of piezo being tested. It could be some kind of filter or an echo sounder transducer for a boat, or a tweeter for a sound system.

So, rather than tackle the difficult high voltage amplifier, it is easier to use a 10 cent resistor to measure the impedance.