How to calculate birefringence in lithium niobate LiNbO3

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    Birefringence Lithium
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Discussion Overview

The discussion revolves around calculating the thickness of lithium niobate (LiNbO3) required to achieve a specific vertical displacement of light (9 microns) for a camera application. Participants explore the optical properties of LiNbO3, particularly its birefringence, and the implications of crystal orientation and thickness on light displacement.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning
  • Experimental/applied

Main Points Raised

  • One participant seeks to understand the relationship between the thickness of LiNbO3 and the desired light displacement, questioning the role of the optical axis and crystal orientation.
  • Another participant emphasizes the importance of the crystal's optic axis orientation relative to the incoming light ray, stating that double refraction occurs only when the light is not aligned with the optic axis.
  • There is a suggestion that the participant's goal resembles the principle of differential interference contrast (DIC) microscopy, raising a question about the choice of LiNbO3 over cheaper alternatives like quartz.
  • One participant provides a formula for calculating the deviation angle between the extraordinary and ordinary rays based on the angle of incidence and the refractive indices.
  • A later reply discusses the potential need to rotate the crystal to achieve the desired displacement and the implications of such adjustments on the ordinary ray.
  • Another participant mentions specific birefringent crystal thicknesses available for purchase and the need to consider the angle of incidence for achieving the desired displacement.
  • One participant offers a calculation example using specific parameters for LiNbO3, indicating that a thickness of 500 micrometers could achieve a 10-micron displacement at a 45-degree angle.
  • There is a suggestion that using two plates oriented differently could allow for adjustable displacement values.
  • One participant questions whether translating the lens or sensor array might be a simpler solution to the problem being addressed.

Areas of Agreement / Disagreement

Participants express various viewpoints on the appropriate crystal cut and orientation, the calculations needed for achieving the desired displacement, and the feasibility of the proposed solution. No consensus is reached on the best approach or the necessity of using LiNbO3 over other materials.

Contextual Notes

Participants note that the calculations depend on specific assumptions about the angle of incidence and the orientation of the crystal. The discussion includes references to mathematical models and optical principles that may not be universally agreed upon.

Lensmonkey
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I am trying to calculate what thickness of LiNbO3 would displace a beam of light 9 microns. I seek to make something like a microscope slide that would displace light in the vertical. I am confused about something else if someone can clarify; for the crystal, I think the "z" axis is "optical axis." I think from what I have read that light that travels this axis in any polarization is unaffected, Is this correct? If so it confuses specifying the dimensions of the slide, as I think of the z dimension as being the thickness. A "z-cut" crystal in this case would not displace at all would it?
 
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Again, you need to know the crystal's optic axis orientation with respect to the incoming ray. For an arrangement such that the input plane is parallel to the so-called principal plane of the (uniaxial) crystal (like the one in the picture below) and is normal to the interface, one can prove that the deviation angle ##\theta_s## between e- and o-rays is given by
$$
\cos \theta_s = \left( \frac{\cos^2\alpha}{n_o^2} + \frac{\sin^2\alpha}{n_e^2} \right) \left( \frac{\cos^2\alpha}{n_o^4} + \frac{\sin^2\alpha}{n_e^4} \right)^{-1/2}
$$
where ##\alpha## is the angle subtended by the incoming ray and optic axis. The e- and o-rays will propagate at the same direction when ##\alpha = 0## or ##90## degree. This means if you want your crystal to exhibit double refraction, you cannot align it such that the incoming ray is parallel with the optic axis.
 

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I am thankful for anyone's time, let me try again.
Goal: a rectangular wafer of that when placed in front of a camera image sensor will displace light(visible) 9 microns vertically, and how to specify it to order it properly!
1) LiNBO3 crystals available for purchase off the shelf are specified as x-cut, y-cut, or z-cut. -which cut is appropriate?
2) With this cut/orientation, what is the calculation to achieve a 9 micron displacement? Could a helpful chap walk me through solving for thickness. I would like to understand and be able to solve for different displacements.
If you are interested in why I am trying to do this, it is to solve a problem my camera has. The camera sensor is a large megapixel one with many rows of pixels for high still resolution. In order to record video the camera must reduce the resolution to the smaller size, the camera throws out the information on 2 out of every 3 horizontal sensor lines. This causes Moire, and Aliasing. I seek to use a LiNBO3 wafer in front of the sensor and behind the lens to displace information that would normally resolve in the middle of the unrecorded lines to the recorded line. So both the information that would normally resolve on the recorded line and the information that would normally have resolved in the unrecorded area are combined (blurred) but only in the vertical. To achieve the a 9 micron shift- Too thick a crystal like calcite or quartz will affect the "back focus" resolving the image in front of the sensor or behind, so focus problems. Too thin, like yttrium and fragility becomes an issue.
I just want to try it as an experiment, and for the fun of solving a problem and learning something new. I am having a hard time pushing through from here and humbly ask for help, or even a referral to someone who might be able to, thanks
 
Here are the X, Y and Z cuts .
http://homepages.uni-paderborn.de/wgs/Dpubl/PRB81_214116_2010.pdf
X and Y cuts should be equivalent, optically.
However you need a cut which is between an X and a Z cut.
To be more precise, double refraction will only occur if the incoming light ray is neither parallel nor perpendicular to the optical axis. In any case the splitting of the rays will depend on the angle of the incident ray.
 
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How thin do you want the crystal to be? The thinnest birefringent crystal wafer provided by newlight http://www.newlightphotonics.com/Birefringent-Crystals/Calcite-Crystals is 0.2 mm. Also, to obtain a specific beam displacement may require the crystal to be rotated, i.e. adjust the incident angle, and this wil cause the ordinary ray to be displaced too. Will such situation be acceptable in your application?
 
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The calculation of the angle can be found in Landau Lifshitz, Electrodynamics of continuous media in the excercises for chapter 98. For normal incidence on a material whose optical axis is at an angle ##\alpha## with the incident ray, the angle ##\theta## of the extraordinary ray relative to the normal of the surface is determined as
## \tan \theta=\frac{(\epsilon_\parallel-\epsilon_\perp)\sin 2\alpha }{\epsilon_\parallel+\epsilon_\perp+(\epsilon_\parallel-\epsilon_\perp)\cos 2\alpha}##
The angle dependence of the denominator can be neglected and the numerator is maximal for ##\alpha=45^\circ##.
If ##d## is the thickness of the wafer, the displacement on exit relative to the ordinary ray is
##\Delta x=d \tan \theta##.
For Li NbO3, the birefringence is 0.09 and ##\epsilon=2.25##. For a wafer with ##\alpha=45^\circ## and d=500 ##\mu##m we find
##\Delta x=10 \mu m##
If you want to be able to adjust the displacement, you could use two plates. If they are oriented alike, the displacements add, while for anti-parallel orientation, they cancel. You can get any value inbetween for the displacement by just changing the angle.
 
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Lensmonkey said:
<snip>
If you are interested in why I am trying to do this, it is to solve a problem my camera has. The camera sensor is a large megapixel one with many rows of pixels for high still resolution. In order to record video the camera must reduce the resolution to the smaller size, the camera throws out the information on 2 out of every 3 horizontal sensor lines. This causes Moire, and Aliasing. I seek to use a LiNBO3 wafer in front of the sensor and behind the lens to displace information that would normally resolve in the middle of the unrecorded lines to the recorded line. So both the information that would normally resolve on the recorded line and the information that would normally have resolved in the unrecorded area are combined (blurred) but only in the vertical. To achieve the a 9 micron shift- Too thick a crystal like calcite or quartz will affect the "back focus" resolving the image in front of the sensor or behind, so focus problems. Too thin, like yttrium and fragility becomes an issue.

Don't you think it would be easier and simpler to just translate the lens or translate (dither) the sensor array?
 

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